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NARA [144]
3 years ago
14

The circumference of the circle-shaped rug is 69.08 inches.

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0
We can find the diameter by dividing the circumference by 3.14
d = 22

Thus, our radius is 11.
r = 11

Now, let's use the area formula (3.14 \cdot r^2) to solve for the area.
a = 3.14 \cdot (11^2) = \boxed{379.94}
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Answer:wanna hang

Step-by-step explanation:

6 0
2 years ago
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Solve for z.<br><br> 3 + 9z = –7 + 10z<br><br> z =
stiv31 [10]
The answer should be z = 10
6 0
3 years ago
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Help please i need answer ASAP
Juli2301 [7.4K]

If the result is reflected over x-axis and vertically stretched by a factor of 5, the result will be g(x) = -5(x - 1)²

<h3>Transformation of functions</h3>

Transformation is a way of changing the position of an object o the xy plane. Given the parent function expressed as

f(x) = x^2

If the function is shifted to the left by unit, then we will have h(x) = (x - 1)²

If the result is reflected over x-axis and vertically stretched by a factor of 5, the result will be g(x) = -5(x - 1)²

Learn more on translation here: brainly.com/question/12861087

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8 0
2 years ago
The function h(t)=-4.87t^2+18.75t is used to model the height of an object projected in the air, where h(t) is the height in met
rodikova [14]
Looking at the graph you can see that the domain of the function is:
 [0, 3.85]
 To find the range of the function, we must follow the following steps:
 Step 1)
 
Evaluate for t = 0
 h (0) = - 4.87 (0) ^ 2 + 18.75 (0)
 h (0) = 0
 Step 2) 
 find the maximum of the function:
 h (t) = - 4.87t ^ 2 + 18.75t
 h '(t) = - 9.74 * t + 18.75
 -9.74 * t + 18.75 = 0
 t = 18.75 / 9.74
 t = 1.925051335
 We evaluate the function at its maximum point:
 h (1.925051335) = - 4.87 * (1.925051335) ^ 2 + 18.75 * (1.925051335)
 h (1.93) = 18.05
 The range of the function is:
 [0, 18.05]
 Answer:
 
Domain: [0, 3.85]
 Range: [0, 18.05]
 option 1
3 0
3 years ago
If m&lt;1=6x+50 and m&lt;2=4x+40 find x
Pepsi [2]
\text{Adjacent angles on a straight line sum up to 180} \textdegree

\text{Therefore }\measuredangle 1 + \measuredangle 2 = 180 \textdegree

\text {Since } \measuredangle 1 = 6x+50 \text { and } \measuredangle 2 = x+40

(6x+50)  + (4x+40) = 180

6x+50 + 4x+40 = 180

10x+90 = 180

10x = 180 - 90

10x = 90

x = 9

Answer: x = 9
8 0
3 years ago
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