The answer is 48. i got this answer by doing 2x6 and i got 12. uri and his family eat 12 slices a day, so you do 12x4 because it asks how many they eat in 4 days. hope this helped!
We can find the acceleration via

We have


Then by definition of average acceleration,

so that


We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

Then


If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
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If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
The length should be 80 feet.
This is because the width is 20 since there are two sides for the width in pen, we have to add 20+20. This would equal 40. Then we need to subtract 40 from 200. 200-40 would be 160. Then since there are two sides for the length, we need to split that in half. 160÷2 would be 80. To double check, you can do 80+80, and that would still be 160. So the length of one side would be 80. But of course, this whole thing would only be right if the pen has four sides(but since I have seen many chicken pens, there were all rectangular)
For this case we have the following function:
y = 9 (3) ^ x
Applying the following transformations we have:
Horizontal translations
Suppose that h> 0
To graph y = f (x-h), move the graph of h units to the right.
y = 9 (3) ^ (x-2)
Vertical translations
Suppose that k> 0
To graph y = f (x) -k, move the graph of k units down.
y = 9 (3) ^ (x-2) - 6
Answer:
2 units to the right
6 units down