9x^2-4x-3 and x=-2
= 9*(-2)^2 - 4*-2 - 3
= (9*4)+8-3
= 36+8-3
= 44-3
=41
Answer:
r = 10q/(p + 30)
so put p+30 in the blank
Step-by-step explanation:
p=10(q - 3r)/r
p = (10q - 30r)/r
pr = 10q - 30r
pr + 30r = 10q
r(p + 30) = 10q
r = 10q/(p + 30)
3. A and 4. C .....I think
A. 10.4 meters
B. 9.3 meters
C. 10.3 meters
This is an isosceles trapezoid, because the two angles are supplementary on the right side.
y is 25 based on the Pythagorean theorem
w is sqrt (850)=29.15
z must be 15
Making a right triangle to look at the altitude
cos 59=a/15, so a is 7.73 between the right corner and the edge of x
That means x is 29.15-2(7.73)=13.69
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The median should be half way between 13.69 and 29.15
That is half their sum, or half of 42.84 or 21.42
That doesn't change the answer above
Once I know the trapezoid is isosceles, the angles at the base have to be 59d and the angles at the top 121d.
please mark brainliest!
