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3 years ago

Which of the following best describes the algebraic expression 10x+2?

2 answers:

7 0

For this case we have the following expression:
10x + 2
There are many different ways to describe the expression.
We will name some of these ways:

1) The expression is a linear function

2) The slope of the line is positive and equal to 10.

3) The cut point of the line with the y axis is 2.

4) The domain of the function is from -inf to inf.

5) The range of the function is from -inf to inf.

elena-14-01-66 [18.8K]3 years ago

7 0

Answer:

Step-by-step explanation:

Ten times the quantity of a number plus two

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Using the triangle find x and y

Elenna [48]

Answer:

see explanation

Step-by-step explanation:

Since the base angle are congruent, both 44° then the triangle is isosceles.

Then the 2 legs are congruent, that is

4x - 7 = 2x + 1 ( subtract 2x from both sides )

2x - 7 = 1 ( add 7 to both sides )

2x = 8 ( divide both sides by 2 )

x = 4

Thus legs are both 4x - 7 = 4(4) - 7 = 16 - 7 = 9 and base = x + 3 = 4 + 3 = 7

As a check 9 + 9 + 7 = 25 → correct

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the base angles from 180 for y, that is

y = 180 - (44 + 44) = 180 - 88 = 92

Finally

x = 4

y = 92

angles are 92°, 44° and 44°

sides are 9, 9 and 7

4 0

3 years ago

list the first three whole numbers greater than 50 that will have a remainder of 7 when you divide by 9

dusya [7]

it's on pic click on pic................................

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(

SSSSS [86.1K]

Answer:

We conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

Step-by-step explanation:

Given the radical expression

$\sqrt{\left(-81\right)x^2}$

simplifying the expression

$\sqrt{\left(-81\right)x^2}$

Remove parentheses: (-a) = -a

$\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}$

Apply radical rule: $\sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=\sqrt{-1}\sqrt{81x^2}$

Apply imaginary number rule: $\sqrt{-1}=i$

$=i\sqrt{81x^2}$

Apply radical rule: $\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt{81}i\sqrt{x^2}$

$=9i\sqrt{x^2}$

Apply radical rule: $\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$=9ix$

Therefore, we conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

7 0

3 years ago

Please answer <br> ( will give brainlst)

serg [7]

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5 0

3 years ago

Read 2 more answers

Help me pleasee<br> Questions r in picture

jok3333 [9.3K]

<h2>Answer:</h2>

$\large \bf\implies\frac{12}{61}$

<h2>Step-by-step explanation:</h2>

<h2>Given :</h2>

$\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...$

nth term

<h2>Solution :</h2>

We have to add 1 in numerator and -10 in denominator because

$\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...[Given]$

$\frac{8 \: + \: 1}{101 \: - \: 10} = \frac{9}{91} \\\\ \frac{9 + 1}{91 - 10} = \frac{10}{81} \\ \\ \frac{10 + 1}{81 - 10} = \frac{11}{71} \\ \\ \frac{11 + 1}{71 - 10} = \frac{12}{61} ...$

The difference is 1 in numerator so we add 1 and the difference is -10 in denominator so we subtract -10.

4 0

2 years ago