The answer would be C) The volume is the same in both cylinders
Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
7/10 > 3/8
I found this by first finding a common denominator, so for this it will be 40. 10 can go into 40 four times, so you do 7x4 and that is 28, so 7/10 is 28/40.
3/8 is 15/40 because 8 goes into 40 five times, so you do 5x3 which is 15, so the fraction is 15/40. 15/40 is less than 28/40 because 28 > 15
The answer to your question is -4