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3 years ago

5

What are the solutions to the equation 6v2 – 17 = –113?

1 answer:

vazorg [7]3 years ago

6 0

The answer is in the ?

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Pls help thankyou real answers only

IceJOKER [234]

Answer:

The Answer Is B

Step-by-step explanation:

I Just Know Because I Was Teacher And This Is 5th Grade Work But Sadly I Cant Explain If You Get It Right Please Mark Me Brainliest

7 0

3 years ago

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I need help with both questions on the screen. if you can only answer one thats fine too!

meriva

Answer:

11. $b = 30$

Step-by-step explanation:

$a^{2} + b^{2} = c^{2}$

Substitute

$16^{2} + b^{2} = 34^{2}$

$256 + b^2 = 1156$

$b^2 = 1156-256\\b^2 = 900$

$b = \sqrt{900}$

$b = 30$

Your welcome and don't forget to say <u>Thanks</u>

7 0

3 years ago

What is the difference between 27,202-3,489

insens350 [35]

27202 - 3489 you can't do 2-9 so you cross out the 0 next to it and put it into a 10 and then turn your to into a 12 so 12 - 9 is 3 then since you have your 0 turned into 10 you do 10-8 you would you get 2 then you can't do 2-4 so we got the cross out your 7 next to it and turn that into a 6 then change 2 into 12 and then do 12 - 4 equals 8 then since you changed your 7
into a 6 6-3 would you get three and then you do 2-0 because there is no number there and you put down 23823 so 23823 is your answer

7 0

3 years ago

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2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

- Erin wants to purchase 3 CDs for $10 each. She has $20. How much

FromTheMoon [43]

Answer:

$10

Step-by-step explanation:

If Erin wants 3 CD's at $10 a piece, that is $30 total. She has $20 which means you find the difference. Total needed: $30 - Money in hand: $20 = $10

Please mark answer as Brainliest and give 5 stars.

3 0

2 years ago

Read 2 more answers