Can you draw only one isosceles triangle that contains an angle of 65
1 answer:
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Given:
Solution:
To solve the equation, it would be best if we remove the root. We remove the root by squaring the equation, but first we need to move the root and the content to the left side.
Then square both side to remove the root
After removing the root, move all terms to the left side
sec² x - 2 sec x + 1 = 0
Do factorization, remember that
a² - 2a + 1 = (a - 1)²
So,
sec² x - 2 sec x + 1 = 0
(sec x - 1)² = 0
sec x - 1 = 0
sec x = 1
= 1
cos x = 1
cos x = cos 0°
x = 0°
Solution:
To solve the equation, it would be best if we remove the root. We remove the root by squaring the equation, but first we need to move the root and the content to the left side.
Then square both side to remove the root
After removing the root, move all terms to the left side
sec² x - 2 sec x + 1 = 0
Do factorization, remember that
a² - 2a + 1 = (a - 1)²
So,
sec² x - 2 sec x + 1 = 0
(sec x - 1)² = 0
sec x - 1 = 0
sec x = 1
cos x = 1
cos x = cos 0°
x = 0°
A. It is a parallelogram so, the formula is just simple base × height; 16cm × 9cm = 144cm²
B. It is a trapezoid so, the formula is base1 + base2 ÷ 2 × height; 25cm+ 44.67cm= 69.67cm ÷ 2 = 34.835cm × 20cm= 696.7cm²
C and D are irregular shapes - the diagram will show you how to do them...
