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vesna_86 [32]
3 years ago
10

What number is 80% of 50? Show your work

Mathematics
2 answers:
klio [65]3 years ago
4 0
80% is the same at 0.80, then all you need to do is multiply that by 50 to get 40
0.80 x 50 = 40
vovangra [49]3 years ago
3 0
0.8 * 50 = 40
40 is 80% of 50
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marishachu [46]
3 x 100 + 2 x 1000
300+ 2000
2300
2.3x10^3
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2 years ago
Rebecca needs 10 1/2 yards of fabric to make quilt.she has one piece of fabric that is 2 1/2 yard and another piece of fabric th
olga55 [171]

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Im pretty sure the answer is c

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Please answer ASAP........
Pani-rosa [81]

Answer:

option number 4

Step-by-step explanation:

Because 1 million contains 6 zeros .and the rules for scientific notation is always in multiple form.

8 0
3 years ago
A triangle has vertices at B(−3, 0), C(2, −1), D(−1, 2). Which series of transformations would produce an image with vertices B″
vichka [17]

We must apply the <em>transformation</em> rules (x, y) → (- x, y) and (x, y) → (x + 1, y + 1) to generate the vertices B''(x, y) = (4, 1), C''(x, y) = (- 1, 0), D''(x, y) = (2, 3). (Right choice: B)

<h3>How to determine the right transformation rules for a set of three points</h3>

In this question we have three points on a <em>Cartesian</em> plane: B(x, y) = (- 3, 0), C(x, y) = (2, - 1), D(x, y) = (- 1, 2). First, we proceed to apply the <em>transformation</em> rule (x, y) → (- x, y):

B'(x, y) = (3, 0), C'(x, y) = (- 2, -1), D'(x, y) = (1, 2)

Then, we use the <em>transformation</em> rule (x, y) → (x + 1, y + 1):

B''(x, y) = (4, 1), C''(x, y) = (- 1, 0), D''(x, y) = (2, 3)

Then, we must apply the <em>transformation</em> rules (x, y) → (- x, y) and (x, y) → (x + 1, y + 1) to generate the vertices B''(x, y) = (4, 1), C''(x, y) = (- 1, 0), D''(x, y) = (2, 3).

To learn more on transformation rules: brainly.com/question/9201867

#SPJ1

7 0
2 years ago
Find a degree 3 polynomial having zeros -5, 1 and 5 and the coefficient of x^3 equal 1
mote1985 [20]

Answer:

x^3 -x^2 -25x +25

Step-by-step explanation:

\text{The roots are,}~ \alpha  = -5,~ \beta = 1 ~ \text{and}~ \gamma = 5\\\\\text{The polynomial is,}\\\\~~~x^3 - (\alpha + \beta + \gamma)x^2+(\alpha \beta + \beta \gamma+ \gamma \alpha)x - \alpha\beta \gamma\\\\=x^3 - (-5+1+5)x^2 +(-5 \cdot 1 + 1 \cdot 5 + 5 \cdot -5)x - (-5)(1)(5)\\\\=x^3 -(0+1)x^2 + (-5+5-25)x +25\\\\=x^3 -x^2 -25x +25

7 0
2 years ago
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