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beks73 [17]
3 years ago
9

Help please someone

Mathematics
2 answers:
Korvikt [17]3 years ago
7 0

Answer:

<S = 60

Step-by-step explanation:

The arc TR and the central angle (T to the center then to R ) are equal.

So the Central angle is 120o

S anywhere on the minor arc is 1/2 the central angle.

<S = 1/2 120

<S = 60

klio [65]3 years ago
4 0

Answer:

60°

Step-by-step explanation:

the relationship between angle RST and its arc TR is:

2m∠(RST)=m(arcTR);

using this formula m∠(RST)=0.5*m(arcTR);

m∠(RST)=60°

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3x + y = 5<br><br> 2x - 2y = -2
Vesnalui [34]

Answer:

Solving the system of equations:

x: 1

y: 2

Step-by-step explanation:

Plug it in to see if it is right, to make sure of course.  Better to be safe than sorry.

7 0
3 years ago
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Which shows the equation y – x = 3 written in slope-intercept form? Question 1 options: y – x – 3 = 0 y – 2 = x + 3 y = 3x y = x
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4 0
3 years ago
Butyric acid ( c3h7cooh) is a weak acid . what is the ph of a 0.0250 m solution of this acid. ka = 1.5 x 10-5 (2 decimal places)
Wewaii [24]

The pH of the weak acid is 3.21

Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :

[H^{+}]=\sqrt{Ka . Ma}

where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.

Since we know the concentration of H+, the pH can be calculated by using

pH = -log[H+]

From question above, we know that :

Ma = 0.0250M

Ka = 1.5 x 10¯⁵

By using the equation, we can determine the concentration of [H+]

[H+] = √(Ka . Ma)

[H+] = √(1.5 x 10¯⁵ . 0.0250)

[H+] = 6.12 x 10¯⁴ M

Substituting the value of [H+] to get the pH

pH = -log[H+]

pH = -log(6.12 x 10¯⁴)

pH = 3.21

Hence, the pH of the weak acid c3h7cooh is 3.21

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8 0
1 year ago
Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0
4 years ago
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Elena-2011 [213]

Answer:

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With a total of 3 10%'s taken off, or in this case, 30% off, we can conclude that the discounted prices of $3.29 is 30% of the original price.

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