Given:
128g sample of titanium
2808J of heat energy
specific heat of titanium is 0.523 J/ g °C.
Required:
Change in temperature
Solution:
This can be solved
through the equation H = mCpT
where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.
Plugging in the
values into the equation
H = mCpT
2808J = (128g) (0.523
J /g °C) T
T
= 41.9 °C
Answer:
D) Oxygen is oxidized and hydrogen is reduced.
Explanation:
In the electrolysis of water, an electric current passes through an electrolytic solution (e.g. aqueous NaCl), leading to the following redox reaction.
H₂O(l) → H₂(g) + 1/2 O₂(g)
The corresponding half-reactions are:
Reduction: 2 H₂O(l) + 2 e⁻ → H₂(g) + 2 OH⁻
Oxidation: 2 H₂O(l) → O₂(g) + 4 H⁺(aq) + 4 e⁻
As we can see, H in water is reduced (its oxidation number decreases from 1 to 0), while O in water is oxidized (its oxidation number increases from -2 to 0).
Answer:
What changes do you notice? The white you see have undergone coral bleaching. At high temperatures, corals may lose their zooxanthellae, causing corals to lose their color and their main source of food. Once bleaching occurs, the coral colony usually dies.
Explanation:
study well
Arigato
Fill in the blanks in order w/ these numbers:
1. 2 1 2 1
2. 3 1 1
3. 1 2 1 2
4. 2 1 1
5. 4 3 2
6. 1 1 2
Hope this helps.
Answer:
The answer to your question is P2 = 280 mmHg
Explanation:
Data
Pressure 1 = P1 = 400 mmHg
Volume 1 = V1 = 1.75 L
Pressure 2 = ?
Volume 2 = 2.5 L
Process
1.- Use Boyle's law to solve this problem
P1V1 = P2V2
-Solve for P2
P2 = P1V1 / V2
2.- Substitution
P2 = (400)(1.75) / 2.5
3.- Simplification
P2 = 700 / 2.5
4.- Result
P2 = 280 mmHg
