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Stels [109]
4 years ago
7

Name at least three types of energy associated with a microwave

Chemistry
1 answer:
schepotkina [342]4 years ago
8 0
Kinetic, radiation, and electricity.
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State two uses of periscope​
adoni [48]
Uses Of Periscope
It is used in submarines to determine the distance of a torpedo and helps in deciding the right time for the attack.
It is used in a nuclear reactor to observe the chemical reactions that are taking place.
In military periscopes are used to observe from their hiding position. Hi
7 0
3 years ago
Isopropanol major species present when dissolved in water
timofeeve [1]

Answer : Isopropanol molecules ( C₃H₈O) are the major species present when dissolved in water.

Explanation :

Compounds are of 2 types.

1) Ionic compounds : These are formed by the transfer of electrons from a metal to a non metal.

When ionic compounds are dissolved in water, they get separated into ions.

Therefore the major species present in case of an ionic compound are ions.

2) Molecular (Covalent) compounds: These are formed by sharing of electrons among 2 or more non metals.

Covalent compounds are further categorized as

a) Polar covalent : Polar covalent compounds partially dissociate to form ions.

Therefore the major species in case of polar covalent compounds are the undissociated molecules and ions.

b) Non polar covalent : Non polar covalent compounds are unable to dissociate and they remain in molecular form when dissolved. So the major species in case of a non polar compound are undissociated molecules only.

Isopropanol is a non polar covalent compound. As discussed above it will have undissociated isopropanol molecules as major species.

Hence Isopropanol molecules ( C₃H₈O) are the major species present when dissolved in water.


5 0
3 years ago
A sample of 10.0 grams of carbon dioxide gas is contained in a tank with a volume of 6.0 L so that the pressure inside the tank
Snezhnost [94]

Answer:

49°C

Explanation:

Let's apply the Ideal Gases Law in order to solve this question:

P . V = n . R . T

Pressure = 1 atm

Volume = 6 L

n = number of moles → 10 g. 1mol /44g = 0.227 moles

R = Ideal Gases Constant

We replace data: 1 atm . 6 L = 0.227 mol . 0.082 . T

6 atm.L / ( 0.227 mol . 0.082) = T

T° = 322 K

We convert T° from K to °C → 322 K - 273 = 49°C

7 0
3 years ago
For each described change, determine the generally expected impact on a salt's solubility. LABEL No solubility change, SOLUBILIT
Anna [14]

Answer:

A- Solubility decrease.

B- Solubility increase.

C- No solubility change.

Explanation:

Hello!

In this case, since the solubility of salt stands for the maximum amount of salt that can be added to a specific mass of water, usually 100 g; we need to take into account that for table salt in aqueous solution, the higher the temperature the larger the solubility and the lower the temperature the smaller the solubility; it means that more salt is dissolved in the same mass of water at higher temperatures and vice versa. Therefore, A- would decrease the solubility as the solution is cooled down and B- would increase the solubility as the solution is heated up.

Moreover, since the mass of water is assumed to remain the same, adding more salt do not affect the solubility but increase the degree of saturation of the solution up to supersaturated, yet the solubility remains unchanged.

Best regards!

4 0
3 years ago
A chemist prepares a solution of silver(I) nitrate AgNO3 by measuring out ×4.7102μmol of silver(I) nitrate into a 450.mL volumet
Veseljchak [2.6K]

The concentration in /mmolL of the chemist's silver(I) nitrate solution is 0.01047 mmoles/litre.

Explanation:

Data given:

Number of moles of AgNO3 in micro mole 4.7102micromol.

The concentration is supposed to be in mmol so the micromole will be converted to milimole.

So, 1 micromole = 0.001 millimole

hence, 4.712micromole will be 0.004712 millimole.

Volume is given as 450ml which is converted into L

to convert ml into L it is divided by 1000

so 0.45 L is the volume.

Molarity or concerntration is calculated by the formula,

molarity = \frac{number of moles}{volume in litres}  

putting the values in the formula:

molarity = \frac{0.0047103}{0.45}

              = 0.01047 mmoles/litre is the molarity of AgNO3 solution in 450 ml of solution.

3 0
4 years ago
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