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jonny [76]
3 years ago
14

Your cell phone plan cost $39.99 per month plus $0.13 for each text message you send or receive. You have at most $45 to spend o

n your cell phone. What is the maximum amount of text messages you can send or receive next month?
Mathematics
2 answers:
gavmur [86]3 years ago
8 0

Answer:

390  posts

Step-by-step explanation:

Blababa [14]3 years ago
5 0
390 is the answer , hope this helps
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Ay bruv I need to see the answer choices to help

Step-by-step explanation:

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3 years ago
Question 8 of 25<br> Which of the following is the quotient of the rational expressions shown here?
Alla [95]

Answer:

  B.  (5x+5)/(x²-2x)

Step-by-step explanation:

As with numerical fractions, division by a rational expression is equivalent to multiplication by its reciprocal.

<h3>As a multiplication problem</h3>

  \dfrac{5}{x-2}\div\dfrac{x}{x+1}=\dfrac{5}{x-2}\times\dfrac{x+1}{x}

<h3>Product of rational expressions</h3>

As with numerical fractions, the product is the product of numerators, divided by the product of denominators.

  =\dfrac{5(x+1)}{x(x-2)}=\boxed{\dfrac{5x+5}{x^2-2x}}

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2 years ago
What is 2/3÷-3/5 as an improper fraction
rodikova [14]

Answer: -10/9

Step-by-step explanation: is this what you were looking for

8 0
3 years ago
Please help veryyy urgent due today!!!!!!
Musya8 [376]
42 is the answer....
4 0
3 years ago
There are premium tickets costing $99 each and rest are regualr tickets costing $25 each. A pile of 120 tickets have a total val
polet [3.4K]

Answer:

There are 38 premium tickets and 82 regular tickets in a pile.

Step-by-step explanation:

Given,

Total number of tickets = 120

Total amount = $5812

Solution,

Let the number of premium tickets be x.

And the number of regular tickets be y.

Total number of tickets is the sum of total number of premium tickets and  total number of regular tickets.

So the equation can be written as;

x+y=120\ \ \ \ \ equation\ 1

Again,total amount  is the sum of total number of premium tickets multiplied by cost of each premium ticket and  total number of regular tickets multiplied by cost of each regular ticket.

So the equation can be written as;

99x+25y=5812\ \ \ \ equation\ 2

Now We will multiply equation 1 by 25 we get;

x+y=120\\25(x+y)=120\times25\\25x+25y= 3000 \ \ \ \ equation\ 3

Now Subtracting equation 3 from equation 2 we get;

(99x+25y)-(25x+25y)=5812-3000\\\\99x+25y-25x-25y=2812\\\\74x=2812\\\\x=\frac{2812}{74}=38

We will now substitute the value of x in equation 1 we get;

x+y=120\\38+y=120\\y=120-38\\y=82

Hence There are 38 premium tickets and 82 regular tickets in a pile.

3 0
3 years ago
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