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kaheart [24]
3 years ago
12

a data set includes the following test scores:75,82,62,78.The score on a retake is 96.it the retake score replaces the lowest te

st grade, how is the mean affected
Mathematics
1 answer:
Savatey [412]3 years ago
7 0

Answer:

Increase by 8.75

Step-by-step explanation:

75+82+67+72=296

296/4= 74

74 = Original Mean

75+82+96+78=331

New mean 82.75

82.75-74=8.75

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1.64 points as a mix number in simplest form
zhuklara [117]
The correct answer is 41/25
8 0
3 years ago
A square pool has a side length of x feet. a uniform border around the pool is 1 foot wide. the total area of the pool and the b
Alex73 [517]
----------------------------------------
Define x:
----------------------------------------
Let x be the length of the pool.

Length of the pool and its border = x + 1 + 1
Length of the pool and its border = x + 2

----------------------------------------
Given area = 361 ft², find x:
----------------------------------------
(x+2)² = 361
x+ 2 = √361
x + 2 = 19
x = 19 - 2
x = 17

----------------------------------------
Find Length of the pool:
----------------------------------------
Length of the pool = x = 17 feet

----------------------------------------
Find Area of the pool:
----------------------------------------
Area = 17 x 17 
Area = 289 ft²

------------------------------------------------------------
Answer: Area of the pool = 289 ft²
------------------------------------------------------------

5 0
3 years ago
A closet contains n pairs of shoes. If 2r shoes are chosen at random, (where 2r < n), what is the probability that there will
Pie
We are choosing 2
2
r
shoes. How many ways are there to avoid a pair? The pairs represented in our sample can be chosen in (2)
(
n
2
r
)
ways. From each chosen pair, we can choose the left shoe or the right shoe. There are 22
2
2
r
ways to do this. So of the (22)
(
2
n
2
r
)
equally likely ways to choose 2
2
r
shoes, (2)22
(
n
2
r
)
2
2
r
are "favourable."

Another way: A perhaps more natural way to attack the problem is to imagine choosing the shoes one at a time. The probability that the second shoe chosen does not match the first is 2−22−1
2
n
−
2
2
n
−
1
. Given that this has happened, the probability the next shoe does not match either of the first two is 2−42−2
2
n
−
4
2
n
−
2
. Given that there is no match so far, the probability the next shoe does not match any of the first three is 2−62−3
2
n
−
6
2
n
−
3
. Continue. We get a product, which looks a little nicer if we start it with the term 22
2
n
2
n
. So an answer is
22⋅2−22−1⋅2−42−2⋅2−62−3⋯2−4+22−2+1.
2
n
2
n
⋅
2
n
−
2
2
n
−
1
⋅
2
n
−
4
2
n
−
2
⋅
2
n
−
6
2
n
−
3
⋯
2
n
−
4
r
+
2
2
n
−
2
r
+
1
.
This can be expressed more compactly in various ways.
4 0
3 years ago
Can someone helPPPPPPPPPPPPPPPPPP
andrezito [222]
I believe it’s option #3. hopefully that helps :)
4 0
2 years ago
Anyone know how to do tables?
dimaraw [331]
I think table a but i’m not 100% sure, sorry
7 0
3 years ago
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