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DedPeter [7]
2 years ago
12

The perimeter of the rectangle is 146 units. What is the length of the longCharlene puts together two isosceles triangles so tha

t they share a base, creating a kite. The legs of the triangles are 10 inches and 17 inches, respectively. If the length of the base for both triangles is 16 inches long, what is the length of the kite’s other diagonal?er side?
Mathematics
1 answer:
Minchanka [31]2 years ago
5 0

Answer:

21 inches.

Step-by-step explanation:

From the question, we are given the following parameters or data or information: The legs of the triangles are 10 inches and 17 inches, perimeter of the rectangle is 146 units and length of the base for both triangles is 16 inches long.

Step one: the first step to do in this question is to determine or Calculate the value for the height of the smaller triangle.

Thus, 10^2 = (16/2)^2 + (b1)^2.

b1 = √ (100 - 64) = √ 36 = 6.

Step two: the second step to do in this question is to determine or Calculate the value for the height of the bigger triangle.

17^2 = (16/2)^2 + (b2)^2.

b2 = √ (289 - 64) = √ 225 = 15.

Step three: this is the lat step and it involves the addition of our values in step one and two above, that is;

6 + 15 = 21.

Thus, length of the kite’s other diagonal = 21 inches.

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The coordinates of the image of P(3,-4) under a reflection in the x-axis are:
lesantik [10]

Answer:

D. (-3,-4)

Step-by-step explanation:

PLACE YOUR GRAPH TOWARDS A MIRROR.....

8 0
2 years ago
8 + 8r = 3 + 3r can anyone can help me out​
MAVERICK [17]

Answer:r = -1

Step-by-step explanation:

8+8r-(3+3r)=0

We add all the numbers together, and all the variables

8r-(3r+3)+8=0

We get rid of parentheses

8r-3r-3+8=0

We add all the numbers together, and all the variables

5r+5=0

We move all terms containing r to the left, all other terms to the right

5r=-5

r=-5/5

r=-1

Hope this helps

6 0
2 years ago
Read 2 more answers
Consider the following equation of the form dy/dt = f(y)dy/dt = ey − 1, −[infinity] < y0 < [infinity](a) Sketch the graph
kotegsom [21]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

a) The graph of  f(y) versus y. is shown on the second uploaded image

b) The critical point is at y = 0  and the solution is asymptotically unstable.

c)The phase line is shown on the third uploaded image

d) The sketch for the several graphs of solution in the ty-plane  is shown on the fourth uploaded image

Step-by-step explanation:

Step One: Sketch The Graph of  f(y) versus y

Looking at the given differential equation

       \frac{dy}{dt} = e^{y} - 1 for -∞ < y_{o} < ∞

 We can say let \frac{dy}{dt} = f(y) =e^{y} - 1

Now the dependent value is f(y) and the independent value is y so to sketch is graph we can assume a scale in this case i cm on the graph is equal to 2 unit for both f(y) and y and the match the coordinates and after that join the point to form the graph as shown on the uploaded image.

Step Two : Determine the critical point

   To fin the critical point we have to set   \frac{dy}{dt} = 0

       This means e^{y} - 1 = 0

                          For this to be possible e^{y} = 1

                          which means that  e^{y} = e^{0}

                          which implies that y = 0

Hence the critical point occurs at y = 0

meaning that the equilibrium solution is y = 0

As t → ∞, our curve is going to move away from y = 0  hence it is asymptotically unstable.

Step Three : Draw the Phase lines

A phase line can be defined as an image that shows or represents the way an ODE(ordinary differential equation ) that does not explicitly depend on the independent variable behaves in a single variable. To draw this phase line , draw the y-axis as a vertical line and mark on it the equilibrium, i.e. where  f(y) = 0.

In each of the intervals bounded  by the equilibrium draw an upward

pointing arrow if f(y) > 0 and a downward pointing arrow if f(y) < 0.

      This phase line would solely depend on y does not matter what t is

On the positive x axis it would get steeper very quickly as you move up (looking at the part A graph).

For  below the x-axis which stable (looking at the part a graph) we are still going to have negative slope but they are going to be close to 0 and they would take a little bit longer to get steeper  

Step Four : Draw a Solution Curve

A solution curve is a curve that shows the solution of a DE (deferential equation)

Here the solution curve would be drawn on the ty-plane

So the t-axis(x-axis) is its the equilibrium  that is it is the solution

If we are above the x-axis it is going to increase faster and if we are below it is going to decrease but it would be slower (looking at part A graph)

5 0
2 years ago
Please help!!!!! I’ll give you brainliest
Nikolay [14]

Answer:

A=32

B=3

C=7

Step-by-step explanation:

Caitlyn surveyed 100 students to find out their favorite class. There were 29 students who enjoyed biology and 35 students who enjoyed English. There were 12 students who did not enjoy Biology, English, or Math.

29 like Biology so to find B you subtract. 29-6-5=3

35 like English so to find C 35-3-5-20=7

Total of 100 students subtract what you know to find A.

100-15-6-5-3-7-20-12=32

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3 years ago
Use the diagram to find the measure of each angle. Enter the number only.
Pavlova-9 [17]

9514 1404 393

Answer:

  a = 64, b = 90, c = 26, d = 90, e = 26, f = 120, g = 120, h = 60,

  i = 56, j = 124, k = 56

Step-by-step explanation:

Vertical angles are congruent; linear pairs are supplementary; two angles dividing a right angle are complementary. These are the angle relations you need to know to solve this.

__

Working from the top and from the given angles, ...

  h = 60°

  f = g = 180° -h = 120°

  j = 124°

  k = i = 180° -124° = 56°

  a = 64°

  b = d = 90°

  c = e = 90° -64° = 26°

In summary, measures in degrees are ...

  a = 64, b = 90, c = 26, d = 90, e = 26, f = 120, g = 120, h = 60,

  i = 56, j = 124, k = 56

7 0
2 years ago
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