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DedPeter [7]
3 years ago
12

The perimeter of the rectangle is 146 units. What is the length of the longCharlene puts together two isosceles triangles so tha

t they share a base, creating a kite. The legs of the triangles are 10 inches and 17 inches, respectively. If the length of the base for both triangles is 16 inches long, what is the length of the kite’s other diagonal?er side?
Mathematics
1 answer:
Minchanka [31]3 years ago
5 0

Answer:

21 inches.

Step-by-step explanation:

From the question, we are given the following parameters or data or information: The legs of the triangles are 10 inches and 17 inches, perimeter of the rectangle is 146 units and length of the base for both triangles is 16 inches long.

Step one: the first step to do in this question is to determine or Calculate the value for the height of the smaller triangle.

Thus, 10^2 = (16/2)^2 + (b1)^2.

b1 = √ (100 - 64) = √ 36 = 6.

Step two: the second step to do in this question is to determine or Calculate the value for the height of the bigger triangle.

17^2 = (16/2)^2 + (b2)^2.

b2 = √ (289 - 64) = √ 225 = 15.

Step three: this is the lat step and it involves the addition of our values in step one and two above, that is;

6 + 15 = 21.

Thus, length of the kite’s other diagonal = 21 inches.

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ANSWER

\begin{gathered} a_n=ar^{n\text{ - 1}} \\ a_8\text{ = \$38.26} \end{gathered}

EXPLANATION

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a_n=ar^{n\text{ - 1}}

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To find the common ratio, we divide a term by its preceeding term.

Let us divide the price of the second month from the first.

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\begin{gathered} r\text{ = }\frac{72}{80} \\ r\text{ = 0.9} \end{gathered}

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\begin{gathered} a_8\text{ = 80 }\cdot0.9^{(8\text{ - 1)}} \\ a_8\text{ = 80 }\cdot0.9^7 \\ a_8\text{ = \$38.26} \end{gathered}

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