Find three solutions of the equation (x^2-9)(x^3-8)=0

1 answer:

7 0

(x^2-9)(x^3-8)=0

as you can see that (x^2-9) is in the form of a^2 - b^2 which equals (a+b)(a-b)

x^2 - 9
= (x)^2 -(3)^2
= (x+3)(x-3)

now, the equation becomes
(x+3)(x-3)(x^3-8)=0

(x+3) =0
x = -3

(x-3) = 0
x = 3

x^3 -8 = 0
x^3 = 8
x = cube rt. 8
= 2

so, the three solutions are -3, 3 and 2.

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8_murik_8 [283]

Answer:

the volume of sand is $50 ft^{3}$

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, rectangular prism.

Given data

$Length l= 4 ft Width w= 5ft\\Height h = 3ft$

if the sandbox is filled with sand of $2\frac{1}{2 } ft$ deep the volume of the sand in the box will be calculated based on the the depth of the sand