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dexar [7]
3 years ago
10

Evaluate 5 - 3(-2) + 1-3|​

Mathematics
2 answers:
Naya [18.7K]3 years ago
6 0

Answer:

9

Step-by-step explanation:

5 - 3 (-2) + 1- 3

5 - (- 6) + 1 - 3

5 + 6 + 1 - 3

11 + 1 - 3

12 - 3

9

<h2>the bold means what is happening to get to the total answer</h2>

marishachu [46]3 years ago
5 0

Answer:

9

Step-by-step explanation:

5 - 3(-2) + 1-3

5 + 6 - 2

11 - 2

9

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Find the lateral area of the cone in terms of π.
Andreyy89

Answer:

15\pi\ cm^{2}

Step-by-step explanation:

we know that

The lateral area of the cone is equal to

LA=\pi rl

where

r is the radius of the base

l is the slant height

we have

r=3\ cm

Applying the Pythagoras Theorem find the slant height

l^{2}=3^{2} +4^{2}\\ \\l^{2}=25\\ \\l=5\ cm

substitute in the formula

LA=\pi (3)(5)=15\pi\ cm^{2}

8 0
3 years ago
4. (4)5 =<br> a. 12<br> b. 13<br> c. 14<br> d. 15
Airida [17]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

  • (4 {}^{3} ) {}^{5}

  • (4{}^{3 \times 5} )

  • 4 {}^{15}

therefore, the Correct choice is d) 15

6 0
2 years ago
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I have 4 factors. Three of my factors are 1, 2, and 6. What is my fourth factor?
SIZIF [17.4K]

The 4th factor would be 3. You would find this out through a factor tree. If you don't know the original number when you start you look at your numbers. A factor of 1 usually goes with the highest number, assuming that the number 6 is the highest factor, that would be the original number. As 2 is the other known factor than we know that 3 has to be the last factor, because 2 x 3 = 6. It cannot be the number 12 because then there would be 6 factors not the needed 4.

7 0
3 years ago
2x - 3 = - ( 4x + 9 )
mafiozo [28]

2x-3 = -(4x+9)

2x-3 = -4x-9

2x+4x=3-9

6x=-6

x=-1

3 0
3 years ago
Suppose the test scores for a college entrance exam are normally distributed with a mean of 450 and a s. d. of 100. a. What is t
svet-max [94.6K]

Answer:

a) 68.26% probability that a student scores between 350 and 550

b) A score of 638(or higher).

c) The 60th percentile of test scores is 475.3.

d) The middle 30% of the test scores is between 411.5 and 488.5.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 450, \sigma = 100

a. What is the probability that a student scores between 350 and 550?

This is the pvalue of Z when X = 550 subtracted by the pvalue of Z when X = 350. So

X = 550

Z = \frac{X - \mu}{\sigma}

Z = \frac{550 - 450}{100}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 350

Z = \frac{X - \mu}{\sigma}

Z = \frac{350 - 450}{100}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a student scores between 350 and 550

b. If the upper 3% scholarship, what score must a student receive to get a scholarship?

100 - 3 = 97th percentile, which is X when Z has a pvalue of 0.97. So it is X when Z = 1.88

Z = \frac{X - \mu}{\sigma}

1.88 = \frac{X - 450}{100}

X - 450 = 1.88*100

X = 638

A score of 638(or higher).

c. Find the 60th percentile of the test scores.

X when Z has a pvalue of 0.60. So it is X when Z = 0.253

Z = \frac{X - \mu}{\sigma}

0.253 = \frac{X - 450}{100}

X - 450 = 0.253*100

X = 475.3

The 60th percentile of test scores is 475.3.

d. Find the middle 30% of the test scores.

50 - (30/2) = 35th percentile

50 + (30/2) = 65th percentile.

35th percentile:

X when Z has a pvalue of 0.35. So X when Z = -0.385.

Z = \frac{X - \mu}{\sigma}

-0.385 = \frac{X - 450}{100}

X - 450 = -0.385*100

X = 411.5

65th percentile:

X when Z has a pvalue of 0.35. So X when Z = 0.385.

Z = \frac{X - \mu}{\sigma}

0.385 = \frac{X - 450}{100}

X - 450 = 0.385*100

X = 488.5

The middle 30% of the test scores is between 411.5 and 488.5.

7 0
3 years ago
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