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dexar [7]
2 years ago
10

Evaluate 5 - 3(-2) + 1-3|​

Mathematics
2 answers:
Naya [18.7K]2 years ago
6 0

Answer:

9

Step-by-step explanation:

5 - 3 (-2) + 1- 3

5 - (- 6) + 1 - 3

5 + 6 + 1 - 3

11 + 1 - 3

12 - 3

9

<h2>the bold means what is happening to get to the total answer</h2>

marishachu [46]2 years ago
5 0

Answer:

9

Step-by-step explanation:

5 - 3(-2) + 1-3

5 + 6 - 2

11 - 2

9

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0 = x because 0 + 5 = 5 plus 2 = 7
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8

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3 0
2 years ago
Whats the distance between (-8,-7) (8,-4)
balandron [24]
To find the distance between points, use the distance formula.

Distance formula: \sqrt{ (x_{2} -  x_{1})^{2} + ( y_{2} -  y_{1})^{2} }

Plug in your values for x_{2},  x_{1},  y_{2},  y_{1} using (-8, -7) and (8, -4) and solve.

\sqrt{(8 - (-8))^{2}+(-4 - (-7))^{2}}
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8 0
3 years ago
Please answer ASAP
labwork [276]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

A 12 cm cone with a dome on top of it that has an 8 cm diameter

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{Volume\:of\:the\:figure = 334.93\:cm^3}}}\end{array}}\qquad\quad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

6 0
3 years ago
F(x)=x^2-x^3 <br> what's the value of f(-2)
Anvisha [2.4K]
(-2)^2-(-2)^3

=4-(-8)

=4+8

=12
4 0
3 years ago
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