Using the binomial distribution, it is found that there is a 0.0555 = 5.55% probability that more than 3 of these selected children have three siblings.
<h3>What is the binomial distribution formula?</h3>
The formula is:
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem, for the parameters, we consider that:
- 10% of the 9-year old children in a town have three siblings, hence p = 0.1.
- Fifteen 9-year old children are selected at random, hence n = 15.
The probability that more than 3 of these selected children have three siblings is given by:
In which:
Then:
P(X > 3) = 1 - 0.9445 = 0.0555
0.0555 = 5.55% probability that more than 3 of these selected children have three siblings.
More can be learned about the binomial distribution at brainly.com/question/24863377
Answer:
Angle AOD and Angle DOB are supplementary
Step-by-step explanation:
AOB is straight(180°) Line DO is a line that creates two angles
Yes, The correct answer is
NO = 52 cm
Answer:
There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
is the Euler number
is the mean in the given time interval.
The problem states that:
The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.
To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.
There are 5 weekdays, with a mean of 0.1 calls per day.
The weekend is 2 days long, with a mean of 0.2 calls per day.
So:
If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?
This is 
. So:
There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.
