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blondinia [14]
3 years ago
13

Other than improvements in hygiene, give two reasons for the low death rate from infectious diseases in modern hospitals.

Biology
1 answer:
DerKrebs [107]3 years ago
6 0
Low death rate from infectious diseases in modern hospitals are attributable to modern hospitals having isolation facilities, where infectious patients are quarantined, and having better technological equipments used to diagnose and treat infections in its early stages.

Hospitals now have areas that cater to different types of medical conditions. Areas like the intensive care units, labor and birthing rooms, isolated rooms, etc. Unlike hospitals in the early ages where everyone is placed in wards regardless of the extent of their sickness.

Vaccinations are also readily available for everyone which lessens the chances of acquiring infectious diseases and spreading them to unsuspecting people.



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Answer:

Habitat Isolation

Explanation:

Ecological, or habitat, isolation occurs when two species that could interbreed do not because the species live in different areas.

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Where did the carbon in all living things on earth come from?
soldier1979 [14.2K]

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What is the role of dna helicase?
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Helikazlar tüm canlılar için hayatî önem taşıyan bir enzim sınıfıdır. Nükleik asitlerin fosfodiester omurgası üzerinde hareket ederek birbirlerine hidrojen bağlarıyla bağlanmış nükleik asit ipliklerini (DNA'nın, RNA'nın veya RNA-DNA hibritlerinin) ayrıştırır.

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Explain why bacterial cellsouter memarane ruptures when the cells
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6 0
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g If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time
Elenna [48]

Answer:

a. 8.1 milligrams

b. 40.07 hours

c. 8.859 milligrams

Explanation:

If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time can be modeled by

A_{t}=10e^{-0.0173t}

Where A(t) = amount of Valium remaining in the blood after t hours

t = time or duration after the drug is taken

a. we have to calculate the amount of drug remaining in the bloodstream after 12 hours

A_{12}=10e^{-0.0173\times12}

A_{12}=10e^{-0.2076}

                = 10×0.81253

                = 8.1 milligrams

b. In this part we have to calculate the time when A(t) = 5 milligrams

5=10e^{-0.0173\timest}

\frac{5}{10}=e^{-0.0173t}

0.5 = e^{-0.0173t}

Now we take natural log on both the sides of the equation.

ln(0.5) = ln(e^{-0.0173t})

-0.69314 = -0.0173t

t = \frac{0.69314}{0.0173}

t = 40.0658

 ≈ 40.07 hours

c. In this part we have to calculate the rate, by which amount of drug will decay in the bloodstream after 7 hours.

A_{7}=10e^{-0.0173\times7}

A_{7}=10e^{-0.1211}

              = 10×0.8859

              = 8.859 milligrams

6 0
3 years ago
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