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nevsk [136]
3 years ago
8

PLEASE HELP ASAP!!!!!!!!!

Mathematics
1 answer:
serg [7]3 years ago
6 0
A.(2,3)
B.(5,5)
C.(7,3)
D.(5,2)

Can someone help meh. Trying to reach Ace tank.
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PLEASEEE HELP I WILL MARK YOU BRAINIEST!!!
lisabon 2012 [21]

Answer:

26

Step-by-step explanation:

duh....

7 0
3 years ago
What is the median of the data values less than the median called?
ivann1987 [24]
A quartile is a type of quantile. The first quartile (Q1) is defined as the middle number between the smallest number and themedian of the data set. The second quartile (Q2) is themedian of the data. The third quartile (Q3) is the middle valuebetween the median and the highest value of the data set.
3 0
4 years ago
Read 2 more answers
Mega Movies hosted a film premiere on Friday night. They charged $9 for adults and $6 for children. One hundred twenty-seven adu
Oxana [17]

x = number of adult tickets

y = number of children tickets

9x + 6y = 1053

x+y = 127 so x = 127 - y

replace x = 127 - y into 9x + 6y = 1053

9(127 - y) + 6y = 1053

1143 -9y + 6y = 1053

-3y = 1053 -1143

-3y = -90

y = 30

x = 127 - 30

x = 97

answer: 97 adults and 30 children




3 0
3 years ago
Three students wrote expressions on their dry-erase boards.
OlgaM077 [116]

Answer:

Student 2 and Student 3

Step-by-step explanation:

Student 2

-(5r - 3s + 1)

= - 5r +3s - 1

Student 3

= - 5r +3s - 1

3 0
3 years ago
Solve the system of equations by the addition method.<br> 1 - 3x = -5y - 8<br> 6x<br> 3y = -5
Advocard [28]

-3x = -5y -8~~~....(i) \\\\6x -3y = -5 ~~......(ii)\\\\\text{Multiply  equation (i) by 2 and do (i) + (ii):}\\\\2 \cdot (-3x) + 6x  -3y = 2(-5y-8)  + (-5)\\\\\implies -6x +6x -3y = -10y -16 -5 \\\\\implies -3y   = -10y -21\\\\\implies -3y +10y =-21\\\\\implies 7y = -21 \\\\\implies y = -\dfrac{21} 7 = -3\\\\\text{Substitute}~y =-3~ \text{in equation (ii):} \\\\6x - 3(-3) = -5\\\\\implies 6x +9  = -5\\\\\implies 6x = -5 -9 = -14\\\\\implies x = -\dfrac{14}6 = - \dfrac{7}3\\

\text{Hence}~ (x,y) = \left(-\dfrac 73, -3 \right)

3 0
3 years ago
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