The capital formation of the investment function over a given period is the
accumulated capital for the period.
- (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.
- (b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.
Reasons:
(a) The given investment function is presented as follows;

(a) The capital formation is given as follows;

From the end of the second year to the end of the fifth year, we have;
The end of the second year can be taken as the beginning of the third year.
Therefore, for the three years; Year 3, year 4, and year 5, we have;

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87
(b) When the capital stock exceeds $100,000, we have;
![\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%20%5Cmathbf%7B%5Cleft%5B1000%20%5Ccdot%20%20e%5E%7B0.1%20%5Ccdot%20t%7D%7D%20%2B%20C%20%5Cright%5D%5Et_0%7D%20%3D%20100%2C000)
Which gives;




The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.
Learn more investment function here:
brainly.com/question/25300925
Answer:
and
Step-by-step explanation:
Note that if
then 
Functions
do not have vertical asymptotes at all.
Vertical asymptotes have functions
Functions
and
have the same vertical asymptotes (when
).
Functions
and
have the same vertical asymptotes (when
). See attached diagram
Answer:
You can cancel your investment without wasting a lot of money.
Step-by-step explanation:
Short-term means that you dont have it for a long time, so you could basically wait it out and then cancel.
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Https://www.algebra.com/algebra/homework/Linear-equations/Linear-equations.faq.question.798537.html
Answer:
63.4°
Step-by-step explanation:
Given that AB and BC are the legs of the right triangle, then opposite to angle A is side BC and adjacent to angle A is side AB.
By definition, the tangent of angle A is:
tan(∠A) = opposite leg / adjacent leg
tan(∠A) = BC/AB
tan(∠A) = 12/6
∠A = arctan(2)
∠A = 63.4°