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Viktor [21]
3 years ago
7

I’m reviewing for a state test plz help I know it’s keep change flip but what do we get and what’s the letter

Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0
The correct answer is C 4/9 x 8
This is because when dividing fractions, flip the second fraction and then change the division sign to multiplying sign
Hope this helps!
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−2(x+1/4)+1=5 PLEASE HELP
PilotLPTM [1.2K]

Answer: x=−9/4

Step-by-step explanation:

Let's solve your equation step-by-step.

−2(x+14)+1=5

Step 1: Simplify both sides of the equation.

−2(x+14)+1=5(−2)(x)+(−2)(14)+1=5(Distribute)−2x+

−1

2

+1=5

(−2x)+(

−1

2

+1)=5(Combine Like Terms)

−2x+

1

2

=5

−2x+

1

2

=5

Step 2: Subtract 1/2 from both sides.

−2x+

1

2

−

1

2

=5−

1

2

−2x=

9

2

Step 3: Divide both sides by -2.

−2x

−2

=

9

2

−2

x=

−9

4

7 0
2 years ago
Read 2 more answers
How to find the y- intercept of y=3^x+9x-14
Bas_tet [7]
Your y-intercept would be (0,-13)
8 0
2 years ago
Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose
Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}


In which

x is the number of sucesses


e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Poisson mean:

\mu = 0.2

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164


0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}&#10;

P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819

P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164&#10;

P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so p = 0.181

We want to find P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671

0.671 = 67.1% probability that neither contains a missing pulse

8 0
3 years ago
A spotlight at a dance club flashes every 25 seconds. Another spotlight flashes every 30 seconds. Both lights just flashed . Aft
bazaltina [42]

find the least common multiple of 25 and 30, which is 150

 so they will flash at the same time every 150 seconds which equals 2.5 minutes

8 0
3 years ago
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What is -9685 divided by 8?
anastassius [24]

Answer:

\frac{-9685}{8}  =    - 1210.625

7 0
3 years ago
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