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Andreyy89
3 years ago
10

If the length of a rectangle is x + 4 and the width of the rectangle is 2x + 9 what would the perimeter of the rectangle be? be

sure to simplify your answer.
Mathematics
1 answer:
ss7ja [257]3 years ago
5 0

Hello!

To find the perimeter of any rectangle, use the formula P = 2l + 2w.

In this formula, l is the length and w is the width. Given that the width is 2x + 9 and the length is x + 4, we can find the perimeter.

P = 2(x + 4) + 2(2x + 9)

P = 2x + 8 + 4x + 18

P = 6x + 26

Therefore, the perimeter of the rectangle is 6x + 26.

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The solution would be 75911*10^10/462500 or 1.64132 x 10^9

Step-by-step explanation:

7 0
3 years ago
3/4 + 3/4 + 3/4 = 9 x ?
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3 years ago
12 cm<br> 8 cm<br> Find the volume of the cylinder
ki77a [65]

Answer:

ubstitute the value of the radius r = 8.0 cm height h = 12.0 cm into the formula to find the volume. Pi (π) is approximately equal to 3.14 .

π x 82 cm2 x 12 cm

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π x 64.0 cm2 x 12 cm

Multiply 64.0 cm2 and 12 cm

π x 768.0 cm3

Combine π and 768.0 cm3

The result can be shown in multiple forms.

Exact Form

Volume = 768.0π cm3

∴ Volume of Cylinder radius 8 cm and height 12 cm is 768.0π cm3

Decimal Form

Volume = 2411.52 cm3

Step-by-step explanation:

5 0
3 years ago
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max2010maxim [7]

Answer:

1. 14

2. 10

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3 0
3 years ago
A closet is is 5 feet wide, 3 feet long, and 6 feet tall. A box with dimensions 2 ft × 3 ft × 2 ft is inside the closet.
Veseljchak [2.6K]

Answer:

78 cm³ of space is left inside the closet.

Step-by-step explanation:

Given that,

A closet is is 5 feet wide, 3 feet long, and 6 feet tall. A box with dimensions 2 ft × 3 ft × 2 ft is inside the closet.

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= 78 cm³

So, 78 cm³ of space is left inside the closet.

5 0
3 years ago
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