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3 years ago

15

What is the slope-intercept form of the equation below? 12x + 5y = -10

2 answers:

VashaNatasha [74]3 years ago

7 0

Answer:

y=-12/5x-2

Step-by-step explanation:

laila [671]3 years ago

6 0

Answer:

93

Step-by-step explanation:

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Plug in the value of x

Inessa [10]

Answer: yes

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Help me solve the out and inputs of the table

velikii [3]

The in is -5 the out for 7 is -21 the out for -3 is 9the infor 15 is -5 the out for -10 is 30

5 0

3 years ago

Solving equations and Inequalities 1 ) -10p=2(p-12)

MArishka [77]

The answer is 2 = p
Explanation: Here the goal is to get the variable "p" by itself, so first your have to distribute 2 to (p-12) which gives you -10p = 2p-24. Then you add 10p on both sides so that the variable is on one side. Then you add 24 to both sides. After that you divide 12 from both sides, giving you 2 = P

-10P = 2(p-12)
-10p = 2p-24
+10p +10p
0 = 12p-24
+24 +24
24 = 12p
24÷12 = 12p÷12
2 = p

5 0

4 years ago

A right triangle has a hypotenuse length of 12, and one side length of 9. find the missing side length. do the side lengths form

Rina8888 [55]

Use the Pythagorean theorem:

$a^2+b^2=c^2$

c - a hypotenuse

a, b - legs

We have: a = 9 and c = 12. Substitute:

$9^2+b^2=12^2$

$81+b^2=144$ <em>subtract 81 from both sides</em>

$b^2=63\to b=\sqrt{63}\\\\b=\sqrt{9\cdot7}\\\\b=\sqrt9\cdot\sqrt7\\\\ \boxed{b=3\sqrt{7}}$

A Pythagorean triple consists of three positive integers a, b and c, such that

$a^2+b^2=c^2$ .

$b=3\sqrt{7}$ is not positive integer.

<h3>The sides of the triangle do not form a pythagorean triple.</h3>

5 0

3 years ago

The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate

soldi70 [24.7K]

Answer:

a) $V = 33510.322\,in^{3}$ , b) $A_{s} = 5026.548\,in^{2}$ , c) $\% V = 0.450\,\%$ , $\%A_{s} = 0.300\,\%$ .

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

$V = \frac{4}{3}\pi \cdot r^{3}$

$A_{s} = 4\pi \cdot r^{2}$

a) The volume of the sphere is:

$V = \frac{4}{3}\pi \cdot (20\,in)^{3}$

$V = 33510.322\,in^{3}$

b) The surface area of the sphere is:

$A_{s} = 4\pi \cdot (20\,in)^{2}$

$A_{s} = 5026.548\,in^{2}$

c) The total differentials for volume and surface area of the sphere are, respectively:

$\Delta V = 4\pi\cdot r^{2}\,\Delta r$

$\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)$

$\Delta V = 150.796\,in^{3}$

$\Delta A_{s} = 8\pi\cdot r \,\Delta r$

$\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)$

$\Delta A_{s} = 15.080\,in^{2}$

Relative errors are presented hereafter:

$\%V = \frac{\Delta V}{V}\times 100\%$

$\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%$

$\% V = 0.450\,\%$

$\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%$

$\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%$

$\%A_{s} = 0.300\,\%$

4 0

3 years ago