First, let's expand the right side. Now our equation is

Now, we gather all the terms with x in it on the left side, and the numbers without x on the right. We get:

And then we can make this

We divide both sides by 12 to get x on its own, so x = 13/12 or 1.08
So if it’s 2/12 it would be 1 flaw in every 6 light bulbs. so if there were 18 light bulbs there would be 3 flaws (6 * 3 is 18)
- 9 + 7
-2
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Answer:
9 5/12
Step-by-step explanation:
2 2/3 + 6 3/4
find a common denomenator. For 3 and 4, it would be 12.
2 8/12 + 6 9/12
add
8 17/12
12 goes into 17 one time, with 5 left over
9 5/12