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Valentin [98]
3 years ago
8

Solve this problem in your notebook using all four steps. Harvey is 3 times as old as Jane. The sum of their ages is 48 years. F

ind the age of each. Jane is _____ a0 years old. Harvey is ____ a1 years old.
Mathematics
2 answers:
jolli1 [7]3 years ago
8 0

Answer: The jane is 12 years old and Harvey is 36 years old.

Explanation:

Let jane's age is defined by J and Harvey's age is defined by H.

It is given that the Harvey is 3 times as old as Jane. It means the age of Harvey is 3 times of the age of jane.

H = 3J      ..... (1)

It also given that the sum their ages is 48.

H + J  = 48     ..... (2)

Using equation (1), Put H = 3J,

3J + J =48

4J = 48

J = 12

Substitute this value is equation (1).

H = 3(12)

H = 36

Therefore, the Jane's age is 12 and the Harvey's age is 36.

Reil [10]3 years ago
3 0

Answer:

Jane is 12 and Harvey is 36

Step-by-step explanation:


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Expressions can be represented as equations, and vice versa.

A possible situation is as follows:

<em>John is 15 years old, and his age is 3 more than 5 times his brother's age</em>

The equation is given as:

\mathbf{5p + 3 = 15}

This means that:

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<u>Step-by-step explanation:</u>

I think you mean (a) find the zeros and (b) describe the end behavior

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                       Degree  =  6

(b) End behavior is determined by the following two criteria:

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Answer:

Step-by-step explanation:

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