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3 years ago

What’s this answe ?? Helpppp!!!

Mathematics

1 answer:

mr Goodwill [35]3 years ago

7 0

the surface area for this is 3 cm2 you take 1/2*6= 3

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What is the difference of 23× and 9×

allsm [11]

23x and 9x are alike terms so
23x-9x
14x

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2 years ago

SOMEONE HELP ???? Select steps that could be used to solve the equation 1+ 3x = -x+4

Alex

Answer:

a) add x , subtract 1 and divide by 4

The solution of given equation $x = \frac{3}{4}$

Step-by-step explanation:

Given equation 1+3 x = -x +4

Add 'x' on both sides , we get

1 + 3 x + x = - x + x +4

1 + 4 x = 4

Subtract '1' on both sides , we get

1+4 x -1 = 4 -1

4 x = 3

Dividing '4' on both sides, we get

$\frac{4x}{4} = \frac{3}{4}$

$x = \frac{3}{4}$

Final answer:-

The solution of given equation $x = \frac{3}{4}$

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3 years ago

The side of an Equileteral triangle is 12cm. What is its Area?

elena55 [62]

Answer:

A = 62.35 cm²

Step-by-step explanation:

Use the area formula A = $\frac{\sqrt{3}a^2}{4}$ , where a is the side length.

Plug in the values:

A = $\frac{\sqrt{3}(12^2)}{4}$

A = $\frac{\sqrt{3}(144)}{4}$

A = 62.35 cm²

3 0

3 years ago

What is the slope of this line? Enter your answer in the box.

tiny-mole [99]

Step-by-step explanation:

The slope of a line characterizes the direction of a line. To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points .

6 0

2 years ago

Read 2 more answers

A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of

notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.01 = 0.99$ , so Z = 2.327.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031$

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.0001 = 2.327\frac{0.0003}{\sqrt{n}}$

$0.0001\sqrt{n} = 2.327*0.0003$

$\sqrt{n} = \frac{2.327*0.0003}{0.0001}$

$(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2$

$n = 48.73$

Rounding up

49 measurements are needed.

7 0

2 years ago