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stealth61 [152]
3 years ago
12

The side of an Equileteral triangle is 12cm. What is its Area?

Mathematics
1 answer:
elena55 [62]3 years ago
3 0

Answer:

A = 62.35 cm²

Step-by-step explanation:

Use the area formula A = \frac{\sqrt{3}a^2}{4}, where a is the side length.

Plug in the values:

A = \frac{\sqrt{3}(12^2)}{4}

A = \frac{\sqrt{3}(144)}{4}

A = 62.35 cm²

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Give the formula for a function with domain (5, ∞) that has the following properties:
KATRIN_1 [288]

Answer:

The area under the curve y = f(x) at x-axis, on the interval x E (5, ∞) is equal to 7.

Step-by-step explanation:

Solution

Given that:

f(x) = 7√x-5

The function of domain is:

D = x-5 > 0

x>5

so,

x← (5, ∞)

Now,

(1) The sequence root function is always known as positive, i.p defined from x E (5, ∞)

i.p =√x-5

Thus,

7/√x-5 >0

Therefore f(x) = 7/√√x-5 which is a positive integer, which is defined in domain x E (5, ∞).

Each value exist a real and unique values of f(x)

Now,

The function f(x) is continuous and over the interval(5, ∞)

Note: Kindly find an attached copy of part to the solution of this given question below

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bz%7D%7B3%7D%2B4%3D%20%5Cfrac%7B5%7D%7B6%7D%20" id="TexFormula1" title=" \frac{z}{
natka813 [3]
\frac{z}{3}+ \frac{12}{3}= \frac{5}{6} ⇒ \frac{z+12}{3}= \frac{5}{6}

z+12= \frac{5\cdot3}{6}=\boxed{2.5}

z=2.5-12

\boxed{\boxed{\boxed{z=-9.5}}}
4 0
3 years ago
Read 2 more answers
Consider lim t → 0+ ( −2 sin(4t) sin(4t) + 2 t cos(4t) ) . using a table of values, the limiting value is
Andrej [43]
Since this is not a rational function (with undetermined values in the denominator), but just a normal expression, we can just substitute t with the value toward which the function is approaching. Since this is a continuous function, it doesn't matter from which side it's approaching 0. In this case, let t=0, then sin(4t)=0, cos(4t)=1, then -2 sin^2(4t)+2tcos(4t)=0. 
3 0
3 years ago
What is the solution to the equation? square root -2x-5-4=x A. -7 and -3 B. 3 and 7 C. -3 D. 7
Alexxx [7]

Answer:

3

Step-by-step explanation:

step1 Isolate the square root on the left hand side

    Original equation

    √2x-5-4 = -x

    Isolate

    √2x-5 = 4-x

step2 eliminate the radical on the left hand side

    Raise both sides to the second power

    (√2x-5)2 = (4-x)2

    After squaring

    2x-5 = x2-8x+16

step3 Solve the quadratic equation

    Rearranged equation

    x2  - 10x  + 21 = 0

    This equation has two rational roots:

      {x1, x2}={7, 3}

step4 Check that the first solution is correct

    Original equation, root isolated

    √2x-5 = 4-x

    Plug in 7 for  x  

     √2•(7)-5 = 4-(7)

     Simplify

     √9 = -3

     Solution does not check

     3 ≠ -3

step5 Check that the second solution is correct

    Original equation, root isolated

    √2x-5 = 4-x

    Plug in 3 for  x  

     √2•(3)-5 = 4-(3)

     Simplify

     √1 = 1

     Solution checks !!

    Solution is:

     x = 3

3 0
3 years ago
8. Solve the system of equations using substitution.
Elodia [21]

Answer:

D

Step-by-step explanation:

In order to solve this we need to plug in the answer choices and make sure they work for BOTH answers!

Let us start with option A. (6,3)  3 = 4(6) + 6     = 3 = 30 This is automaticly wrong because 3 doesnt equal 30. There is no need to try it on the second equation since the first one was wrong.

Next answer choice, B  (3,6)  6 = 2(3) =   6=6. The second equation works perfect for this. Now we have to make sure that it works for the first one as well. 6 = 4(3) + 6   = 6 = 18 which is wrong.

Next, C.  (1,2)   2 = 2(1) = 2=2 Right now lets check the other equation.

2 = 4(1) + 6 = 2=10. Wrong

Last, D. (-3, -6)    -6 = 2(-3)  = -6 = -6 Right now lets check the other equation.

-6 = 4(-3) + 6 = -6 = -6. CORRECT. Answer choice D works for both equations.

Sorry for the wait of response.

8 0
3 years ago
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