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3 years ago

Is 0.777777 a repeating decimal ?

Mathematics

2 answers:

kodGreya [7K]3 years ago

7 0

No. It ends after 6 digits.

horsena [70]3 years ago

6 0

Answer: no

Step-by-step explanation:

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Find the inverse of each relation<br><br> (-3,-7) (0,-1) (5,9) (7,13)

masha68 [24]

(-7,-3) (-1,0) (9,5) and (13,7)

8 0

3 years ago

What is the equation of the line that passes through the point (-8,5) and has a slope of -1/4

tresset_1 [31]

Answer:

$y=\frac{-1}{4} x+3\\$

Step-by-step explanation:

$(y-5)=\frac{-1}{4} (x--8)\\(y-5)=\frac{-1}{4} (x+8)\\y=\frac{-1}{4} x-\frac{8}{4}+5 \\y=\frac{-1}{4} x-2+5\\y=\frac{-1}{4} x+3\\$

5 0

2 years ago

Read 2 more answers

PLZ HELP ASAP, LINKS AND ABSURD ANSWERS WILL BE REPORTED! I WILL MARK BRAINLIEST!!

Stels [109]

The closest answer I can see you type is: 35/1.66666666

This is because you divide 21 by 18 which (if you divide 21 by 1.666666 you get 18) and whatever you do to 1 side, you do to the other, then you get 35/1.6666666

7 0

2 years ago

How many terms are in this expression? v2+9

makvit [3.9K]

I believe its 3. But i think you should wait for someone else to answer cause I might be wrong.

4 0

3 years ago

Express the given expanded numeral as a Hindu-Arabic numeral. (8x102) +(4x10)(2x1)

Marysya12 [62]

Answer:

The Hindu-Arabic numeral form of the given expanded numeral is 842.

Step-by-step explanation:

The given expanded numeral is

$(8\times 10^2)+(4\times 10)+(2\times 1)$

We need to express the given expanded numeral as a Hindu-Arabic numeral.

According to Hindu-Arabic numeral the given expanded numeral is written as

$(8\times 10^2)+(4\times 10)+(2\times 1)=(8\times 100)+(4\times 10)+(2\times 1)$

On simplification we get,

$(8\times 10^2)+(4\times 10)+(2\times 1)=(800)+(40)+(2)$

$(8\times 10^2)+(4\times 10)+(2\times 1)=842$

Therefore the Hindu-Arabic numeral form of the given expanded numeral is 842.

5 0

3 years ago

Is 0.777777 a repeating decimal ?​

Is 0.777777 a repeating decimal ?