The quadratic equation that models the height of the rocket after t seconds is:
s(t) = -4.9t² + 39.2t.
<h3>What is the quadratic function for a projectile's height?</h3>
Considering the height in meters, the equation is given by:
s(t) = -4.9t² + v(0)t + h(0)
In which:
- v(0) is the initial velocity, in m/s.
- h(0) is the initial height, in m.
In this problem, we have that v(0) = 39.2, h(0) = 0, hence the equation is:
s(t) = -4.9t² + 39.2t.
More can be learned about quadratic functions at brainly.com/question/24737967
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Answer:
Step-by-step explanation:
A =1/2 *h (x+y)
A =hx+hy/2
A*2 =hx+hy
2A =hx+hy
2A - hy = hx
(2A -hy)/h = x
Answer: A, C, D and E
Step-by-step explanation:
Answer:14
Step-by-step explanation:
h(x)=-3x+2
h(-4)=-3(-4)+2
h(-4)=12+2
h(-4)=14
Well just substitute y (the first equation) into the second equation.
So
5x-4(5-3x)=-3
Then just solve the equation from there.
5x-20+12x=-3
17x=17
x=1
and if you need y, y=2
