Answer:
The concentration of the HNO3 solution is 0.103 M
Explanation:
Step 1: Data given
Volume of the unknow HNO3 sample = 0.125 L
Volume of 0.200 M Ba(OH)2 = 32.3 mL = 0.0323 L
Step 2: The balanced equation
2HNO3(aq) + Ba(OH)2 ( aq ) ⟶ 2H2O ( l ) + Ba( NO3)2 (aq)
Step 3:
n2*C1*V1 = n1*C2*V2
⇒ n2 = the number of moles of Ba(OH)2 = 1
⇒ C1 = the concentration of HNO3 = TO BE DETERMINED
⇒ V1 = the volume of the HNO3 solution = 0.125 L
⇒ n1 = the number of moles of HNO3 = 2
⇒ C2 = the concentration of Ba(OH)2 = 0.200 M
⇒ V2 = the volume of Ba(OH)2 = 0.0323 L
1*C1 * 0.125 L = 2*0.200M * 0.0323 L
C1 = (2*0.200*0.0323)/0.125
C1 = 0.103 M
The concentration of the HNO3 solution is 0.103 M
Answer: 3.613x10^24
Explanation: Avogadro’s number represents the number of atoms in one mole of substance: 6.022x10^23 atoms/mole. Multiplying the number of moles by this number reveals that, in this sample, 3.613x10^24 atoms of methane are present.
The answer & explanation for this question is given in the attachment below.
Answer:
B. Carry oxygen, nutrients, waste, & to fight pathogens
Explanation:
The circulatory system refers to all organs and tissues involved in carrying blood and lymph around the body.
The circulatory system carries oxygenated blood from the heart to cells and deoxygenated blood back to the heart.
Nutrients are carried in the blood to cells in different parts of the body and waste products are also carried from cells in the blood.
White blood cells is a component of blood in the circulatory system that fights off diseases.
Answer:
This reaction is an example of Hydrohalogenation reaction of alkene.
In this reaction the double bond of alkene acts as nucleophile.
This reaction follows Markovnikov's rule i.e. the bromide will add to more substituted carbon atom.
This is because the carbocation intermediate formed during the reaction is is more stable due to its secondary structure.
The final product is called 2-Bromopropane.