Answer:
The concentration of the HNO3 solution is 0.103 M
Explanation:
Step 1: Data given
Volume of the unknow HNO3 sample = 0.125 L
Volume of 0.200 M Ba(OH)2 = 32.3 mL = 0.0323 L
Step 2: The balanced equation
2HNO3(aq) + Ba(OH)2 ( aq ) ⟶ 2H2O ( l ) + Ba( NO3)2 (aq)
Step 3:
n2*C1*V1 = n1*C2*V2
⇒ n2 = the number of moles of Ba(OH)2 = 1
⇒ C1 = the concentration of HNO3 = TO BE DETERMINED
⇒ V1 = the volume of the HNO3 solution = 0.125 L
⇒ n1 = the number of moles of HNO3 = 2
⇒ C2 = the concentration of Ba(OH)2 = 0.200 M
⇒ V2 = the volume of Ba(OH)2 = 0.0323 L
1*C1 * 0.125 L = 2*0.200M * 0.0323 L
C1 = (2*0.200*0.0323)/0.125
C1 = 0.103 M
The concentration of the HNO3 solution is 0.103 M
