<h3>
Answer:</h3>
0.819 mol Ag
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
4.93 × 10²³ atoms Ag
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:
![\displaystyle 4.93 \cdot 10^{23} \ atoms \ Ag(\frac{1 \ mol \ Ag}{6.022 \cdot 10^{23} \ atoms \ Ag})](https://tex.z-dn.net/?f=%5Cdisplaystyle%204.93%20%5Ccdot%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20Ag%28%5Cfrac%7B1%20%5C%20mol%20%5C%20Ag%7D%7B6.022%20%5Ccdot%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20Ag%7D%29)
- Divide:
![\displaystyle 0.818665 \ mol \ Ag](https://tex.z-dn.net/?f=%5Cdisplaystyle%200.818665%20%5C%20mol%20%5C%20Ag)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.818665 mol Ag ≈ 0.819 mol Ag
Answer:
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[AR] 3d10 4s2 is the configuration for zinc
Answer:
if I am going to answer I need the set up
Explanation:
please show the set up and I will answer the question