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3 years ago

Are mushroom producing spores asexual or sexual

2 answers:

6 0

I believe it is asexually as a mushroom can produce spores if its the only mushroom for miles. Hope this helps! <span />

Kipish [7]3 years ago

4 0

The answer is
asexually

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PLEASE HELP! It'll mean the world to me

Vikki [24]

Answer:

24 a 2.85

Explanation:

HCl is a powerful acid so it completely ioniz in water

8 0

2 years ago

1. Is water an element ?

earnstyle [38]

Answer:

Explanation:

Water is made up of oxygen and hydrogen. both of those are on the periodic table. water is not an element though

hope this helps!

Please mark me brainliest!

3 0

2 years ago

Read 2 more answers

According to the following reaction, how many grams of potassium sulfate will be formed upon the complete reaction of 23.8 grams

Alexxandr [17]

<u>Answer:</u> The mass of potassium sulfate that can be produced is 73.88 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For KOH:</u>

Given mass of KOH = 23.8 g

Molar mass of KOH = 56.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of KOH}=\frac{23.8g}{56.1g/mol}=0.424mol$

The chemical equation for the reaction of KOH and potassium hydrogen sulfate follows:

$KHSO_4+KOH\rightarrow K_2SO_4+H_2O$

As, potassium hydrogen sulfate is present in excess. It is considered as an excess reagent.

KOH is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of KOH produces 1 mole of potassium sulfate

So, 0.424 moles of KOH will produce = $\frac{1}{1}\times 0.424=0.424moles$ of potassium sulfate

Now, calculating the mass of potassium sulfate from equation 1, we get:

Molar mass of potassium sulfate = 174.26 g/mol

Moles of potassium sulfate = 0.424 moles

Putting values in equation 1, we get:

$0.424mol=\frac{\text{Mass of potassium sulfate}}{174.26g/mol}\\\\\text{Mass of potassium sulfate}=(0.424mol\times 174.26g/mol)=73.88g$

Hence, the mass of potassium sulfate that can be produced is 73.88 grams

8 0

3 years ago

Consider the equilibrium

Kamila [148]

Answer:

The answers are in the explanation

Explanation:

For the equilibrium:

B(aq) + H₂O(l) ⇌ HB⁺(aq) + OH⁻(aq).

By LeChatelier's principle, the increase in the concentration of a reactant (for example) at equilibrium will change the system counteracting the increasing producing more product.

Thus,

A) Will the equilibrium constant for the reaction increase, decrease, or stay the same? Why? .

The equilibrium constant is a thermodynamic constant that stay the same with the addition of a compound.

B) Will the concentration of HB⁺(aq) increase, decrease, or stay the same? Why?

By LeChatelier's principle, the addition of B will induce the formation of more HB⁺(aq) increasing the concentration.

C) Will the pH of the solution increase, decrease, or stay the same? Why?

As the addition of B induce the increasing of OH⁻, the pH of the solution will increase.

I hope it helps!

7 0

3 years ago

Remember to balance the equations first

Semenov [28]

mol CO₂ = 9.6

mol N₂ = 4.8

mol O₂ = 0.8

mol H₂O = 8

<h3>Further explanation</h3>

Reaction

4C₃H₅O₉N₃ → 12CO₂ + 6N₂ + O₂ + 10H₂O

mol CO₂

$\tt \dfrac{12}{4}\times 3.2=9.6$

mol N₂

$\tt \dfrac{6}{4}\times 3.2=4.8$

mol O₂

$\tt \dfrac{1}{4}\times 3.2=0.8$

mol H₂O

$\tt \dfrac{10}{4}\times 3.2=8$

8 0

2 years ago