left[0]=a[0];
for(int i=1;i<=n-1;i++)
left[i]=(left[i-1]*a[i])%M;
right[n-1]=a[n-1];
for(int i=n-2;i>=0;i--)
right[i]=(right[i-1]*a[i])%M;
for query q
if(q==0)
return right[1]%M;
if(q==n-1)
return left[n-2]%M;
return (left[q-1]*right[q+1])%M;
Answer/Explanation:
It is best to use Performance Monitor and Process counters to observe performance.
Cheers
Answer:
1.Execution Unit. 2.Bus interface unit
Explanation:
That means the device is programmed to mark the word as grammatically incorrect, if you double tap the word there should be a correct suggestion of the word instead. This may not always be the right one tho, ask someone experienced if you’re unsure.
