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3 years ago

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A frog has fallen into a pit that is 30m deep. Each day the frog climbs 3m but falls 2m at night. How many days those it takes t

he frog to escape

1 answer:

lions [1.4K]3 years ago

8 0

Answer:

28 days

Step-by-step explanation:

because the frog climbs 3m in the day, but falls 2m at night, it technically climbs 1m every 24 hours. this means after the 1st day, it will have climbed a total of 1m, on the second, it will have climbed a total of 2m, and so on. however, when it gets nearer to the top, that's when things start to change. after the 26th day, it will have climbed 26m. on the 27th day, it will be 27m, but then when it jumps 3m the next day, it will reach 30m total before it falls during the night and it will be able to get out of the hole.

i hope this helps! :)

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Step-by-step explanation:

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Read 2 more answers

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When solving an equation with an absolute value term, you make two separate equations ans solve for x:

Equation 1: |4x-3|-5 = 4

1st add 5 to both sides:

|4x-3| = 9

Remove the absolute value term and make two equations:

4x-3 = 9 and 4x - 3 = -9

Solving for x you get X = 3 and x = -1.5

When you replace x with those values in the original equation the statement is true so those are two solutions.

Do the same thing for equation 2:

|2x+3| +8 = 3

Subtract 8 from both sides:

|2x+3| = -5

Remove the absolute value term and make two equations:

2x +3 = -5

2x+3 = 5

Solving for x you get -1 and 4, but when you replace x in the original equation with those values, the statement is false, so there are no solutions.

The answer is:

C. The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.

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3 years ago

How do you solve -2(3x-1)-3=4x+5-x

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3 years ago

The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term

Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be $1$ , $5$ , and $25$ .

The sum of the first seven terms of the geometric sequence would be $127$ .

Step-by-step explanation:

<h3>1.</h3>

Let $d$ denote the common difference of the arithmetic sequence.

Let $a_1$ denote the first term of the arithmetic sequence. The expression for the $n$ th term of this sequence (where $n\!$ is a positive whole number) would be $(a_1 + (n - 1)\, d)$ .

The question states that the first term of this arithmetic sequence is $a_1 = 1$ . Hence:

The third term of this arithmetic sequence would be $a_1 + (3 - 1)\, d = 1 + 2\, d$ .
The thirteenth term of would be $a_1 + (13 - 1)\, d = 1 + 12\, d$ .

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let $r$ denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

$\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d$ .

Ratio between the third term and the second term of the geometric sequence:

$\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}$ .

Both $(1 + 2\, d)$ and $\left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right)$ are expressions for $r$ , the common ratio of this geometric sequence. Hence, equate these two expressions and solve for $d$ , the common difference of this arithmetic sequence.

$\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}$ .

$(1 + 2\, d)^{2} = 1 + 12\, d$ .

$d = 2$ .

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be $1$ , $(1 + (3 - 1) \times 2) = 5$ , and $(1 + (13 - 1) \times 2) = 25$ , respectively.

These three terms ( $1$ , $5$ , and $25$ , respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be $r = 25 /5 = 5$ .

<h3>2.</h3>

Let $a_1$ and $r$ denote the first term and the common ratio of a geometric sequence. The sum of the first $n$ terms would be:

$\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}$ .

For the geometric sequence in this question, $a_1 = 1$ and $r = 25 / 5 = 5$ .

Hence, the sum of the first $n = 7$ terms of this geometric sequence would be:

$\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}$ .

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3 years ago