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4 years ago

14

If x+3y=7 and y=2 then x equals?

2 answers:

Verdich [7]4 years ago

7 0

X + 3y = 7
y = 2

Substitute

x + 3(2) = 7
x + 6 = 7
x = 1
Hope this helps!<span />

Nina [5.8K]4 years ago

6 0

The answer would be 1

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4 years ago

Question on similar triangles attatched

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Step-by-step explanation:

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2 years ago

Meg withdrew $300 from her account on Saturday. Then she deposited $174.83 into her account on Sunday. Meg wants to know how muc

Travka [436]

The correct answer is $125.17

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3 years ago

Find: (6m5 3 â€"" m3 â€"" 4m) â€"" (â€""m5 2m3 â€"" 4m 6) Write subtraction of a polynomial expression as addition of the additi

aliina [53]

The subtraction in the standard form of the polynomial is $\rm 7m^5-3m^2-3$ .

Given that

Expression; $\rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)$ .

We have to determine

The subtraction of a polynomial.

According to the question

Expression; $\rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)$ .

To find the subtraction of the polynomial follow all the steps given below.

Step1; Write the expression as an additive inverse.

$\rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)\\\\\rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)$

Step2; Rewrite terms that are subtracted as the addition of the opposite.

$\rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)\\\\6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)$

Step3; Group-like terms.

$\rm 6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)\\\\(6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\$

Step4; the resulting polynomial in standard form is,

$\rm (6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\ 7m^5-3m^2-3$

Hence, the subtraction in the standard form of the polynomial is $\rm 7m^5-3m^2-3$ .

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2 years ago

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horsena [70]

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Step-by-step explanation:

Simplify the expression.

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4 years ago

Read 2 more answers