R - 10 = 18 - r
2r = 28
r = 14
By applying Pythagorean theorem, we have proven that the point (-1/2, -√3/2) lies on the unit circle.
<h3>How to prove this point lies on the unit circle?</h3>
In Trigonometry, an angle with a magnitude of -120° is found in the third quarter and as such, both x and y would be negative. Also, we would calculate the reference angle for θ in third quarter as follows:
Reference angle = 180 - θ
Reference angle = 180 - 120
Reference angle = 60°.
For the coordinates, we have:
sin(-120) = -sin(60) = -1/2.
cos(-120) = -cos(60) = -√3/2.
By applying Pythagorean theorem, we have:
z² = x² + y²
z = √((-1/2)² + (-√3/2)²)
z = √(1/4 + 3/4)
z = √1
z = 1.
Read more on unit circle here: brainly.com/question/9797740
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$4.75 per movie and $5.75 per game. See picture for explanation.
Answer:
No and Yes.
Step-by-step explanation:
The inequation is y ≥-x+7 and the pair is (x,y)=(-1,-1). Then:
-1≥ -(-1)+7
-1 ≥ 1+7
-1 ≥ 8, but this is not true, so (-1,-1) is not a solution of y ≥-x+7.
On the other hand, the inequation is y>(3/4)x-5 and the pair is (5,3). Then:
3>(3/4)(5)-5
3>(15/4)-5
3> -5/4 and this is true, so (5,3) is a solution of y>(3/4)x-5.
It would be obtuse.
Hope this helps :)
