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3 years ago

Find the exact value of each expression. sin75° cos(-75°)

Mathematics

2 answers:

suter [353]3 years ago

7 0

Answer:

Step-by-step explanation:

sin 75°

sin(30°+45°)

sin30°*cos45°+cos30°sin45°

1/2*1/ $\sqrt{2}$ + $\sqrt{3}$ /2*1 $\sqrt{2$

1/2 $\sqrt{2}$ + $\sqrt{3}$ /2 $\sqrt{2}$

1+3/2 $\sqrt{2}$

cos(-75°)

-cos(180°-105°)

-cos(-105°)

cos 105°

cos(45°+60°)

cos45°cos60°-sin45°sin60°

1/ $\sqrt{2}$ *1/2-1/ $\sqrt{2}$ * $\sqrt{3}$ /2

1/2 $\sqrt{2$ - $\sqrt{3$ /2 $\sqrt{2}$

1- $\sqrt{3}$ /2 $\sqrt{2}$

tino4ka555 [31]3 years ago

5 0

sin(75)

=0.96

cos(-75)

=0.25

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3 years ago

15 points. Please answer as soon as possible.

abruzzese [7]

Answer:

A. $\frac{(a-b)^{2} +b^{2} }{a^{2}}$

Step-by-step explanation:

So to get the area of a square, we need to find the length of one side.

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We can find the length of a side of the smaller square by using pythagoreans theorem to find the hypotenuse of the triangle formed in the bottom left corner. The length of one side along the x axis is a - b, and the length of the other side, along the y-axis, is b.

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The area of the smaller triangle is C squared to the area of the smaller triangle is

$(a-b)^{2} +b^{2}$

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So the ratio should be

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3 years ago

Find the area of an equilateral triangle (regular 3-gon) with the given measurement. 6-inch radius A = sq. in.

katovenus [111]

$\bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}\qquad 
\begin{cases}
s=length~of\\
\qquad a~side\\
-------\\
s=6
\end{cases}\implies A=\cfrac{6^2\sqrt{3}}{4}\implies A=\cfrac{36\sqrt{3}}{4}
\\\\\\
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3 years ago

On farm there are 200 cows from those 200 cows there are 150 cows that can give milk .in one corral there are 20 cows. How many

LiRa [457]

Here the two samples should be comparable .

The total number of cows in the farm = 200

the total number of cows giving milk = 150

the total number of cows in corral = 20

Suppose total number of cows giving milk in corral = x

The ratio of the total number of cows present to the total number of cows giving milk should be same in farm and corral

so : 200 = 20

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150 x

now we do cross multiplication :

200 x = 150* 20

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SO we expect 15 cows in corral should be giving milk .

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4 0

3 years ago

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