1. We assume, that the number 800 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 800 is 100%, so we can write it down as 800=100%.
4. We know, that x is 8% of the output value, so we can write it down as x=8%.
5. Now we have two simple equations:
1) 800=100%
2) x=8%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
800/x=100%/8%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 8% of 800
800/x=100/8
(800/x)*x=(100/8)*x - we multiply both sides of the equation by x
800=12.5*x - we divide both sides of the equation by (12.5) to get x
800/12.5=x
64=x
x=64
now we have:
8% of 800 tons =64 Tons
I hope this helped!!
Well if you are asking for the 2 values of x, then you would get this by setting each parenthesis to 0 this will result in 2x-6=0 now add the 6 to both sides and get 2x=6 now divide by 2 to get 3 your first x is 3 now lets do the next one, 3x-4=0 add the 4 to both sides and get 3x=4 now divide to get x=4/3 sp your 2 sets would be x=3 and x=4/3
Hope this helped
Answer:
a) 20<h≤30.
b) 26.17 hrs
Step-by-step explanation:
The missing table is shown in attachment.
Part a)
We need to find the class interval that contains the median.
The total frequency is
The median class corresponds to half
That is the 15th value.
We start adding the frequency from the top obtain the least cumulative frequency greater or equal to 15.
2+8+9=19
This corresponds to the class interval 20<h≤30.
Adding from the bottom also gives the same result.
Therefore the median class is 20<h≤30.
b) Since this is a grouped data we use the midpoint to represent the class.
The median is given by :
Answer:
See the proof below.
Step-by-step explanation:
For this case we need to proof the following indentity:
So we need to begin with the definition of tangent, we know that 
and we can do this:
(1)
We also have the following identities:
Now we can apply those identities into equation (1) like this:
(2)
We can divide numerator and denominator from expression (2) by 
we got this:
And simplifying we got:
And that complete the proof.
Answer:
D
Triangle Midsegment
5
10
Step-by-step explanation:
Got it right on the assignment on EDG2020 :)
