Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
The answer would be C
Step-by-step explanation:
Because if you look at the triangles you can where they match up and if you look at the lines you can tell if they match up and C matches that`s how I did it well that`s how I do it when I do math
16 can be expressed as a difference of two prime numbers in two ways, which
is:23 - 7 = 16, 19 - 3 = 16
Among the choices, 16 is expressed as (23 - 7), which is the difference of two prime numbers.
Answer:
$1800
Step-by-step explanation:
12000(1+0.05x 3)
= 13800
13800 - 12000
$1800
