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2 years ago

The area of a rectangle is 79 square feet. The width of the rectangle is 213 feet. What is the length of the rectangle?

Mathematics

1 answer:

sattari [20]2 years ago

8 0

79 ÷ 213=

0.37089201877 feet

You can just put 0.3708

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PLEASE HELP ME!! (50 COINS) (i rlly need help so im giving coins away PLEASE ANSWER IMMEDIATELY!!!)

Archy [21]

Hello from MrBillDoesMath!

Answer:

4( x + 1.5)^2 + 0

Discussion:

4x^2 + 12x + 9 = => factor "4" from first 2 terms

4 (x^2 + 3x) + 9 = => complete the square, add\subtract (1.5)^2

4(x^2 + 3x + (1.5)^2) - 4 (1.5)^2 + 9 =

4 ( x + 1.5)^2 + ( 9 - 4(1.5)^2) = => as (1.5)^2 = 2.25

4 ( x + 1.5)^2 + ( 9 - 4(2.25)) = => as 4 ( 2.25) = 9

4 ( x+ 1.5)^2 + 0

Thank you,

MrB

5 0

2 years ago

Daniel got 86% on his test and he solved 5 points extra credit problem. What would be his new grade on this test?

tensa zangetsu [6.8K]

86%=86/100
86+5=91
91/100=91%

7 0

3 years ago

Write an equation for a circle with center at (5,-2) and diameter of 8 centimeters.

mars1129 [50]

Answer:

$(x-5)^2+(y+2)^2=16$

Step-by-step explanation:

lol brainlessly...

General Circle function: $(x-h)^2+(y-k)^2=r^2$ , where h is the x-coordinate of the center, k is the y-coordinate of the center, and r is the radius.

The radius of the circle is half the diameter so: 8 / 2 = 4

The x-coordinate of the circle is 5

The y-coordinate of the circle is -2

Plug in.

$(x-5)^2+(y-(-2))^2=4^2$

$(x-5)^2+(y+2)^2=16$

5 0

3 years ago

Find the value of x.

Maksim231197 [3]

Answer:

x = 120 degrees

Step-by-step explanation:

50 + 70 = 120

3 0

3 years ago

Read 2 more answers

For the funtion f(x)= (x+7)^5, Find f^-1 (x)

quester [9]

Answer:

The inverse of function $f(x)= (x+7)^5$ is $\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}$

Option A is correct option.

Step-by-step explanation:

For the function $f(x)= (x+7)^5$ , Find $f^{-1} (x)$

For finding inverse of x,

First let:

$y=(x+7)^5$

Now replace x with y and y with x

$x=(y+7)^5$

Now, solve for y

Taking 5th square root on both sides

$\sqrt[5]{x}=\sqrt[5]{(y+7)^5}\\\sqrt[5]{x}=y+7\\=> y+7=\sqrt[5]{x}\\y=\sqrt[5]{x}-7$

Now, replace y with $f^{-1} (x)$

$f^{-1} (x)=\sqrt[5]{x}+7$

So, the inverse of function $f(x)= (x+7)^5$ is $\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}$

Option A is correct option.

6 0

3 years ago