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Rama09 [41]
3 years ago
5

Help me I need help!!!!!!!!!

Mathematics
1 answer:
Nonamiya [84]3 years ago
3 0

is -4 diapers (mark as brainliest)

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There are 6 cups of sugar in 5 batches of cookies. how many cups are in 1 batch
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1.2 cups

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6 cups / 5 batches = 1.2 cups/batch

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2 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
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Lera25 [3.4K]

Answer:

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5 0
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Use the given conditions to write an equation for each line in point-slope form and slope-intercept form.
elixir [45]

Answer:

y = 1/3x        y - 0 = 1/3 (x - 0)

Step-by-step explanation:

slope intercept: y = 1/3x

point slope: y - 0 = 1/3 (x - 0)

6 0
3 years ago
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