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UNO [17]
3 years ago
5

Tanapcalcbr9 5.6.005. - the world population at the beginning of 1990 was 5.3 billion. assume that the population continues to g

row at the rate of approximately 2%/year and find the function q(t) that expresses the world population (in billions) as a function of time t (in years), with t = 0 corresponding to the beginning of 1990. (round your answers to two decimal places.)
Mathematics
1 answer:
Dominik [7]3 years ago
3 0

An increase of 2% per year means the population is multiplied by 1.02 each year. Your exponential function with a base of 1.02 and a scale factor of 5.3 (billion) will look like this:

... q(t) = 5.3×1.02^t

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Please help me on this
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5 * 7 = 35

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The probability that a student uses Smarthinking Online Tutoring on a regular basis is 0.31 . In a group of 21 students, what is
Ivenika [448]

Answer: 0.0241

Step-by-step explanation:

This is solved using the probability distribution formula for random variables where the combination formula for selection is used to determine the probability of these random variables occurring. This formula is denoted by:

P(X=r) = nCr × p^r × q^n-r

Where:

n = number of sampled variable which in this case = 21

r = variable outcome being determined which in this case = 5

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3 years ago
What is x^2+3x-28 factored
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Answer: x^(2)-3x-28=0

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Is this ordered pair a solution to the inequality?<br> (1, 3)<br> 5x+y&lt;-3<br> A.)No<br> B.)Yes
max2010maxim [7]
(1,3) means that x = 1 and y = 3. Let's make substitutions to see what happens with the inequality

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5 + 3 < -3
8 < -3

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3 0
3 years ago
A bank loaned out $21,500 , part of it at the rate of 11% annual interest, and the rest at 10% annual interest. The total intere
Luda [366]

Answer:

The loaned amount at 11 % is $ 19,000

The loaned amount at 10 % is $ 2,500

Step-by-step explanation:

Given as :

The total loan amount = $21,500

The total interest earn = $2,340.00

The rate of interest are 11 %  and 10 %

Let The loan amount at 11 % rate = $P

and The loan amount at 10 % rate = $21,500 - $P

Let The loan took for 1 year

Now,<u> From Simple Interest method </u>

Simple Interest = \dfrac{\textrm Principal\times \textrm Rate\times \textrm Time}{100}

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Or, SI_1 = \dfrac{P\times 11\times \textrm 1}{100}

Similarly

SI_2 = \dfrac{21,500 - P\times 10\times \textrm 1}{100}

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Or, \dfrac{P\times 11\times \textrm 1}{100} + \dfrac{21,500 - P\times 10\times \textrm 1}{100} = $2,340

Or, 11 P - 10 P + 215000 = 234000

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Hence The loaned amount at 11 % is $ 19,000

And     The loaned amount at 10 % is $ 2,500    Answer

8 0
3 years ago
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