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Kay [80]
3 years ago
7

Pls help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Blizzard [7]3 years ago
6 0
According from calculations, you should distributive. when you distribute the equation would be 
12v+3-6v-9= 2v-14+ w
combine like terms and add 14 to both sides.
6v=8= 2v+w
and subtract 2v to both sides
which will leave 
3v+8=w
opps I don't think that's one of the options... hehehe sorry
STatiana [176]3 years ago
3 0
The answer to this question is  4v+8
12v+3-6v-9=2v-14+w
12v+3-6v-9-2v+14=w
12v-6v-2v+14-9+3=w
6v-2v+5+3=w
4v+8=w
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Molly categorized her spending for this month into four categories: Rent, Food, Fun, and Other. The percents she spent in each c
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750

Step-by-step explanation:

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6 times the sum of a number and 5 is 16
Ulleksa [173]
The equation would be 6 times x+5=16. This would be kinda Impossible. But a really close answer is 1.833
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It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

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What decimal is equal to 2/3
Liula [17]

The decimal that is equal to 2/3 is...

0.66666666666

Hope this helps

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