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Kay [80]
4 years ago
7

Pls help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Blizzard [7]4 years ago
6 0
According from calculations, you should distributive. when you distribute the equation would be 
12v+3-6v-9= 2v-14+ w
combine like terms and add 14 to both sides.
6v=8= 2v+w
and subtract 2v to both sides
which will leave 
3v+8=w
opps I don't think that's one of the options... hehehe sorry
STatiana [176]4 years ago
3 0
The answer to this question is  4v+8
12v+3-6v-9=2v-14+w
12v+3-6v-9-2v+14=w
12v-6v-2v+14-9+3=w
6v-2v+5+3=w
4v+8=w
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Please help with #12 im confused<br> that is the key but i dont get it
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Given Equation

\boxed{ \tt \: (8 \sqrt{3}  - 2 \sqrt{2} )(8 \sqrt{3}   + 2 \sqrt{2})}

Step by step expansion:

\dashrightarrow \sf \: (8 \sqrt{3}  - 2 \sqrt{2} )(8 \sqrt{3}   + 2 \sqrt{2})

\\  \\

\dashrightarrow \sf \: (8 \sqrt{3})^{2}  - (2 \sqrt{2}  {)}^{2}

Reason:

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\dashrightarrow \sf \: (8 {}^{2}  \times  { \sqrt{3} }^{2} )- (2 \sqrt{2}  {)}^{2}

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\dashrightarrow \sf \: (64  \times 3 ) - (2 \sqrt{2}  {)}^{2}

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\dashrightarrow \sf \: (64  \times 3 ) - (2 {}^{2} \times   \sqrt{2}  {}^{2}  {)}

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\dashrightarrow \sf \: 192- 8

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\dashrightarrow \sf \: 184

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~BrainlyVIP ♡

4 0
2 years ago
Read 2 more answers
The process of moving a figure to a different location is called:
Kisachek [45]
The process of moving a figure to a different location is called TRANSFORMATION. 
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Someone help, the question is on the attachment.​
gavmur [86]
The answer is y = 2.
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PSYCHO15rus [73]

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