The total number of handshakes was 234.
- The first man shook hands with 12 other men.
- The second man shakes hands with 11 other men, as he had already shaken hands with the first man.
- Like-wise, the last man does not need to shake hands again as every man has already shaken hands with him in their respective turns.
- The number of handshakes among men is 0 + 1 + 2 + … + 12.
- The sum of "n" natural numbers = (n)(n+1)/2
- The number of handshakes among men is 12(13)/2.
- The number of handshakes among men is 78.
- Each man shakes hands with every woman except his spouse.
- Each man shakes hands with 12 other women.
- The number of handshakes between men and women is 13*12.
- The number of handshakes between men and women is 156.
- The total number of handshakes is 78 + 156.
- The total number of handshakes is 234.
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Answer:
it should be the 3rd one
Step-by-step explanation:
Answer:
B.The exponent of the solution is –12, the difference of the original exponents.
C.The coefficient of the solution must be greater than or equal to one but less than 10.
D.The quotient is 3.0 × 
Step-by-step explanation:
We are finding the quotient of the expression below in scientific notation
The following conclusions can be drawn
B.The power of 10 in the solution is –12, the difference of the original exponents.
C.The coefficient is 3, which is greater than or equal to one but less than 10.
D.The quotient is 3.0 ×
Answer:
30b
Step-by-step explanation:
what you do is times 6 and 5 then add b
