Answers:
In these exercices are ilustrated the representations of the fractions
2) Firstly, we have 3 equal segments, each one representing 
, hence:
is <u>3</u> copies of
Let's prove it, taking into account we are adding fractions with the same denominator:
There are <u>4</u> equal parts that make a whole
Four copies of <u></u> make 
or <u>1</u> whole
3) Here we have a line divided into four segments, each one of 
. Hence:
This is 
of a line. is <u>4</u> lengths of
If we draw one more we will have 
or 1 whole.
Then:
<u>5</u> lengths of make or <u>1</u> whole.
4) In this part the answer is in the attached image. If we have two equal segments, each one of 
we will have as a result 
.
If we add another segment, we will have three segments of , having as a result 
Answer:
-3
Step-by-step explanation:
y=mx+ b
m is slope.
mark brainliest
Factoring by grouping usually pairs up the first 2 sets of expressions with the second 2 sets. Ours looks like this, then:
. If we factor out the common x-squared in the first set of parenthesis, along with factoring out the common 5 in the second set, we get this:
. Now the common expression that can be factored out is the (x-9). When we do that, here's what it looks like:
. I'm not sure how far you are going with this. You could set each of those equal to 0 and solve for x in each case. The first one is easy. If x - 9 = 0, then x = 9. The second one involves the imaginary i since x^2 = -5. In that case,
. Hopefully, in what I have given you, you can find what you're looking for.
Divide and u get 6 remainder 6
A quantity that may change
