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3 years ago

Why isn’t it reading the problem right

Mathematics

2 answers:

Andrej [43]3 years ago

8 0

what do we do??? im not understanding the question..lol

Vanyuwa [196]3 years ago

4 0

Just make sure you type is correctly

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28 is increased by 150%. what's the final number

sp2606 [1]

Answer:

Step-by-step explanation:

20x(1+150%)

28x(1+1.5)

28x2.5

5 0

2 years ago

Simplify this expression: cos t(sec t − cos t)

Nostrana [21]

$\cos t \, (\sec t - \cos t)$
$= \cos t \, (\frac{1}{\cos t} - \cos t)$
$= 1 - \cos^2 t$
$= \bf sin^2 t$

5 0

3 years ago

Read 2 more answers

Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .

sergey [27]

Step 1) Divide the figure into separate shapes

Long rectangle: 27 x 5

Triangle: 3 x 4

Middle rectangle: 15 x 7

Small rectangle: 6 x 3

Step 2) Find the area of each shape

Long rectangle: A = 27 x 5 = 135

Triangle: A = 1/2 x 3 x 4 = 6

Middle rectangle: A = 15 x 7 = 105

Small rectangle: 6 x 3 = 18

Step 3) Add all of the areas together

A = 135 + 6 + 105 + 18 = 264 square feet

Hope this helps! :)

8 0

3 years ago

A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages ar

Elenna [48]

Answer:

We conclude that the mean amount packaged is equal to 8.17 ounces.

Step-by-step explanation:

We are given that in a particular sample of 50 packages, the mean amount dispensed is 8.171 ounces, with a sample standard deviation of 0.052 ounces.

Let $\mu$ = population mean amount packaged.

So, Null Hypothesis, $H_0$ : $\mu$ = 8.17 ounces {means that the mean amount packaged is equal to 8.17 ounces}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 8.17 ounces {means that the mean amount packaged is different from 8.17 ounces}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean amount dispensed = 8.171 ounces

s = sample standard deviation = 0.052 ounces

n = sample of packages = 50

So, the test statistics = $\frac{8.171-8.17}{\frac{0.052}{\sqrt{50} } }$ ~ $t_4_9$

= 0.1359

The value of t-test statistics is 0.1359.

Also, the P-value of test-statistics is given by;

the meaning of the p-value is that the p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.001 ounces away from8.17 if the null hypothesis is true.

P-value = P( $t_4_9$ > 0.136) = More than 40% {from the t-table}

Since the P-value of our test statistics is more than the level of significance of 0.01, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean amount packaged is equal to 8.17 ounces.

6 0

3 years ago

[2647]A·[712813914]B=? help me!!!!!!!!!!!!!!!!!!!!!

Amanda [17]

Is this suppose to be an equation or is there something missing here?

3 0

3 years ago