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adell [148]
2 years ago
7

Can someone help me solve pleaseeeee? Asap

Mathematics
2 answers:
Mekhanik [1.2K]2 years ago
6 0

Answer:

\frac{4}{5}

Step-by-step explanation:

Given

\frac{12x-4}{15x-5} ← factorise numerator and denominator

= \frac{4(3x-1)}{5(3x-1)} ← cancel (3x - 1) on numerator and denominator

= \frac{4}{5}

vlabodo [156]2 years ago
4 0

Answer:

If your install bratleby on your device, It will help you with this. But you will have to put in an email. and it will give 10  questions to answer for free. Sorry that I cannot help you with this.

Step-by-step explanation:

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What theorem or postulate can be used to justify that AHIG EAFIE?
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Answer:

ASA

Step-by-step explanation:

There is an included side in between both angles in each triangle.

I hope this helps you out, and as always, I am joyous to assist anyone at any time.

4 0
3 years ago
Graph the line 2x + y = 7.
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Answer:f

Step-by-step explanation:

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2 years ago
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Is the relation a function?
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8 0
3 years ago
Suppose that 1 kg of Sodium-24 is reduced to 0.0156 kg in 90 hours. What is the half-life, in hours, of Sodium-24?​
N76 [4]

Answer:

14.99 hours

Step-by-step explanation:

The formula for half-life is given as,

R/R' = 2ᵃ/ᵇ...................... Equation 1

Where R= Original mass of sodium-24, R' = mass of Sodium-24 after disintegration, a = Total time taken for sodium-24 to disintegrate, b = half-life of sodiun-24.

Given: R = 1 kg, R' = 0.0156 kg, a = 90 hours

Substitute into equation 1 and solve for b

1/(0.0156) = 2⁹⁰/ᵇ

Taking the log of both side

log[1/(0.0156)] = log(2⁹⁰/ᵇ)

log[1/(0.0156)] = 90/b(log2)

90/b = log[1/(0.0156)]/log2

90/b = 6.0023

b = 90/6.0023

b =  14.99 hours

b = 14.99 hours.

Hence the half-life of Sodium-24 is 14.99 hours

7 0
3 years ago
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