Determine the quadrant adding or subtracting periods -10pi/3+2pi=-4pi/3+2pi=2pi/3
which is the second quadrant because
first quadrant is between 0 and pi/2
second quadrant is between pi/2 and pi
third quadrant is between pi and 3pi/2
fourth is between 3pi/2 and 2pi
now we find the terminal angle since it is the second quadrant we use theta'=pi-theta=pi-2pi/3=pi/3
sin(pi/3)=sqrt(3)/2 sin is positive in the second quadrant
cos(pi/3)=-0.5 cos is negative in the second quadrant
tan(pi/3)=sin(pi/3)/cos(pi/3)=-sqrt(3) tan is negative in the second quadrant
Answer:
0.75
Step-by-step explanation:
if you divide 100 by 4 you get 25 so 25 is 1/4 so 25 times 3 gets 0.75 out of 100
Answer:
EF = 6.6
Step-by-step explanation:
Since ABCD is similar to EFGH, then EH is similar to AD. So, we can solve by first dividing 12 by 2 (EH by AD). The quotient of this is 6. This tells us that quadrilateral EFGH is 6 times larger than quadrilateral ABCD, since they are similar. So, with this and the measurement of AB (which is similar to EF), we can now solve for EF. We simply multiply 1.1 (the measurement of AB) by 6 (how many times larger EFGH is compared to ABCD). The product of this is 6.6, our final answer.
Answer:
AW=10
Step-by-step explanation:
In a parallelogram opposite sides are congruent meaning XA and AZ are congruent. YA and AW are congruent. So...
Solving for XA and AZ
XA=AZ
3m=5m-4
-2m=-4
m=2
If YW=10m then 10 x 2 = 20
20 divided by 2 = 10
Answer:
Step-by-step
The sum must be greater than 1 because
1/2 + 1/2= 2/2 or 1
ex
3/4 + 8/4= 11/4
9/16+15/16=24/16
8/8+9/8=17/8
