Answer:
Mass of sodium chloride decomposed = 24.54 g
Explanation:
Given data:
Mass of sodium chloride decomposed = ?
Mass of chlorine gas formed = 15 g
Solution:
Chemical equation:
2NaCl → 2Na + Cl₂
Number of moles of Cl₂:
Number of moles = mass/molar mass
Number of moles = 15 g/ 71 g/mol
Number of moles = 0.21 mol
Now we will compare the moles of Cl₂ with NaCl from balance chemical equation.
Cl₂ : NaCl
1 : 2
0.21 : 2×0.21 = 0.42 mol
Mass of Sodium chloride decompose:
Mass = number of moles × molar mass
Mass = 0.42 mol × 58.44 g/mol
Mass = 24.54 g
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The mass of water produced by the reaction of the 23 g of
is 13.8 g.
The given chemical reaction;

In the given compound above, we can deduce the following;
- molecular mass of
= 28 + (2 x 16) = 60 g - molecular mass of
= 2(18) = 36 g
60 g of
--------- 36 g of water
23 g of
------------- ? of water

Thus, the mass of water produced by the reaction of the 23 g of
is 13.8 g.
- <em>"Your question is not complete, it seems to be missing the following information";</em>
In the reaction of the given compound,
, what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?
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The correct option is D.
When dissolving a substance in a solvent, stirring the solution will increased the rate at which the substance dissolved. This is because, when one stirs a solution, it exposes more surface area of the solute to the solvent, thus, increasing the interaction between the solute and the solvent. The higher the quantity of the solute that is exposed to the solvent, the higher the rate of dissolution of the solute.
Answer:
Explanation:
The formation of ammonia that occurred by the reaction of nitrogen and ammonia is expressed as:
⇄ 
where;
The reactants are:
Hydrogen and nitrogen
The product is ammonia.
For the reaction, the equilibrium constant can be expressed as:
![K = \dfrac{[product]}{[reactants]}](https://tex.z-dn.net/?f=K%20%3D%20%5Cdfrac%7B%5Bproduct%5D%7D%7B%5Breactants%5D%7D)
![K = \dfrac{[NH_3]^2}{[N_2]^3[H_2]^3}](https://tex.z-dn.net/?f=K%20%3D%20%5Cdfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5E3%5BH_2%5D%5E3%7D)
From the equilibrium constant conditions, the formation of ammonia and its decomposition due to its reversible reaction back to hydrogen and nitrogen are equal. It implies that the rate of the forward reaction is also equal to that of the backward reaction.
Thus, during when equilibrium is obtained;
Hydrogen, Nitrogen, and Ammonia are present.