Question

Calculate the [ OH − ] and the pH of a solution with an [ H + ] = 0.090 M at 25 °C . [ OH − ] = M pH = Calculate the [ H + ] and the pH of a solution with an [ OH − ] = 0.00098 M at 25 °C . [ H + ] = M pH = Calculate the [ H + ] and the [ OH − ] of a solution with a pH = 10.15 at 25 °C . [ H + ] = M [ OH − ] =

Answer 1

Answer:  a) $[OH^-]=1.09\times 10^{-13}$ and pH = 1.04

b) $[H^+]=1.02\times 10^{-11}$  and $pH=10.99$

c) $[H^+]=7.08\times 10^{-11}$ and $[OH^-]=1.41\times 10^{-4}$

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$pOH=-\log [OH^-]$

$pH+pOH=14$

a) $[H^+]=0.090M$

$pH=-\log [0.090]=1.04$

$pOH=14-1.04=12.96$

$12.96=-log[OH^-]$

$[OH^-]=1.09\times 10^{-13}$

b) $[OH^-]=0.00098M$

$pOH=-\log [0.00098]=3.01$

$pH=14-3.01=10.99$

$10.99=-log[H^+]$

$[H^+]=1.02\times 10^{-11}$

c) $pH=10.15$

$10.15=-\log [H^+]$

$[H^+]=7.08\times 10^{-11}$

$pOH=14-10.15=3.85$

$3.85=-log[OH^-]$

$[OH^-]=1.41\times 10^{-4}$