Answer:
30 ml of 45% salt solution and 20 ml of 30% salt solution.
Step-by-step explanation:
Let x be the amount of 45% salt solution and y be the amount of 30% salt solution
the two equation will be:
x+y=60 -- A
0.45x+0.3y=0.4(60) -- B
Solve by substitution
Rewrite Equation A
x+y=60
x=60-y --- C
Substitute C into B
0.45(60-y)+0.3y=24
27-0.45y+0.3y=24
-0.15y=-3
y=20
<u>Substitute</u> the y=20 into equation C
x=60-20
x=30
Therefore, there was 30 ml of 45% salt solution and 20 ml of 30% salt solution.
We define the spaces of the man and the woman's independent arrivals.
In this case,
f(man) = 1 (45-15) = 1/30
f(woman)=1/(60-0)= 1/60
f(man)*f(woman) = 1/1800
Probability = P
P (man-woman)< 5 = 1/1800* integral of (y ) with limits of (x+5) and (x-5) from 45 to 15.
P (man-woman) <5 = 1/6
Well first you want to be trying to solve for the same variable in both problems. Lets solve for Y.
This means we must make both equations say " Y="
first we subtract 12x from both sides of "12x-3y=3" which leaves us with
-3y=3-12x and y=4x-1.
you are basically going to merge the 2 problems by adding "1" to both problems and then subtracting "4x" from both as well as subtracting "y" from both. This gets rid of a variable in one problem and essentially puts in to the other in the process.
This leaves you with -4y=4-16x
Can you solve from there?
1 km=0.62 mi
45 km- x mi
x=45*0.621*1=27.95
Answer <span>B)27.96miles</span>
sub
<span>
</span>
since -x^2+x+19=y
<span>
</span>
x=-x^2+x+19+80
<span>
</span>
x=-x^2+x+99
<span>
</span>
0=-x^2+99
<span>
</span>
x^2=99
x=3√11
x=y+80
3√11=y+80
minus 80 both sides
-80+3√11=y
x=3√11
y=-80+3√11
solution
(x,y)
(3√11,-80+3√11)
